[c] Reading from file using read() function

I have to write a program that reads numbers in separate lines each. Is it possible to read only one line of the file and then read an int from the buffer, and so on until the end of file? It is really hard to find good examples of using read and write. My example is kind of working but I'd like to read until it detects '\n' char and then convert buffer into int.

#include <fcntl.h> 
#include <stdio.h> 
#include <string.h>
#include <unistd.h> 
#include <iostream>

int fd[2];

void readFile(int fd) {
    unsigned char buffer[10];
    int bytes_read;
    int k=0;
    do {
        bytes_read = read(fd, buffer, 10); 
        k++;
            for(int i=0; i<10; i++) {
            printf("%c", buffer[i]);
        }
    }
    while (bytes_read != 0); 
}

int tab[50];

int main(int argc, char *argv[]) {
    if(argv[1] == NULL || argv[2] == NULL)   {
            printf("Function requires two arguments!\nGood bye...\n");
            return -1;
    }
    else {
        if (access(argv[1], F_OK) == 0) {
            fd[0] = open(argv[1], O_RDONLY);
        }
        else { 
            fd[0] = open(argv[1], O_WRONLY|O_CREAT|O_SYNC, 0700);
            const int size = 50;
                for(int i=0; i<size; i++) {
                    char buf[10];   
                    sprintf(buf, "%d\n", i+1);
                    write(fd[0], buf, strlen(buf));
                }
                close(fd[0]);
            fd[0] = open(argv[1], O_RDONLY);
            if (access(argv[2], F_OK) == 0) 
                fd[1] = open(argv[2], O_WRONLY);
            else 
                fd[1] = open(argv[2], O_WRONLY|O_CREAT, 0700);
        }
    }

    if (access(argv[2], F_OK) == 0) 
        fd[1] = open(argv[2], O_WRONLY); 
    else 
        fd[1] = open(argv[2], O_WRONLY|O_CREAT, 0700);


    readFile(fd[0]);
    close(fd[0]);
    close(fd[1]);
}

Revised code:

void readFile(int fd) {
    char buffer[10];
    int bytes_read;
    int k = 0;
    do {
        char t = 0;
        bytes_read = read(fd, &t, 1); 
        buffer[k++] = t;    
        printf("%c", t);
        if(t == '\n' && t == '\0') {
            printf("%d", atoi(buffer));
            for(int i=0; i<10; i++) 
                buffer[i]='\0';
            k = 0;
        }
    }
    while (bytes_read != 0); 
}

This question is related to c file

The answer is


Read Byte by Byte and check that each byte against '\n' if it is not, then store it into buffer
if it is '\n' add '\0' to buffer and then use atoi()

You can read a single byte like this

char c;
read(fd,&c,1);

See read()


fgets would work for you. here is very good documentation on this :-
http://www.cplusplus.com/reference/cstdio/fgets/

If you don't want to use fgets, following method will work for you :-

int readline(FILE *f, char *buffer, size_t len)
{
   char c; 
   int i;

   memset(buffer, 0, len);

   for (i = 0; i < len; i++)
   {   
      int c = fgetc(f); 

      if (!feof(f)) 
      {   
         if (c == '\r')
            buffer[i] = 0;
         else if (c == '\n')
         {   
            buffer[i] = 0;

            return i+1;
         }   
         else
            buffer[i] = c; 
      }   
      else
      {   
         //fprintf(stderr, "read_line(): recv returned %d\n", c);
         return -1; 
      }   
   }   

   return -1; 
}

I am reading some data from a file using read. Here I am reading data in a 2d char pointer but the method is the same for the 1d also. Just read character by character and do not worry about the exceptions because the condition in the while loop is handling the exceptions :D

  while ( (n = read(fd, buffer,1)) > 0 )
{   

if(buffer[0] == '\n')
{
  r++;
  char**tempData=(char**)malloc(sizeof(char*)*r);

  for(int a=0;a<r;a++)
  {
    tempData[a]=(char*)malloc(sizeof(char)*BUF_SIZE);
    memset(tempData[a],0,BUF_SIZE);
  }

  for(int a=0;a<r-1;a++)
  {
    strcpy(tempData[a],data[a]);
  }

   data=tempData;

   c=0;
}

else
{
  data[r-1][c]=buffer[0];
  c++;
  buffer[1]='\0';
}

   }