[excel] Application.WorksheetFunction.Match method

I have seen a lot of Topics to the "unable to get the match property of the Worksheetfunction class" problem. But I can't get my code fixed.

Why isn't this code work?

rowNum = Application.WorksheetFunction.Match(aNumber, Sheet5.Range("B16:B615"), 0)

But a few rows higher this code works:

rowNum2 = Application.WorksheetFunction.Match(originCode, Sheet7.Range("B10:B17"), 0)

The only difference between my two lines is that in rowNum2 I used a String for look up and in rowNum a integer. Is it possible that the look up Value needs to be a String?

@Update on my Problem

Select Case service
Case "Low Cost"
MsgBox Sheet5.Cells(16, "B") 'Gets value 0.5
Set Rng = Sheet5.Range("B16:B615")

   If Not IsError(Application.Match("0.5", Rng, 0)) Then 'But jumps to Else
    rowNum = Application.Match(Weight, Rng, 0) 'Weight = 0.5
    MsgBox rowNum
Else
    MsgBox "error"
End If

Case "Standard"

Case "Express"

Case Else

End Select

@UPDATE 2

!!! Take care that "0.5" is a String and not 0.5 So 0.5 is not "0.5" (that was my error in the code)

This question is related to excel vba

The answer is


You are getting this error because the value cannot be found in the range. String or integer doesn't matter. Best thing to do in my experience is to do a check first to see if the value exists.

I used CountIf below, but there is lots of different ways to check existence of a value in a range.

Public Sub test()

Dim rng As Range
Dim aNumber As Long

aNumber = 666

Set rng = Sheet5.Range("B16:B615")

    If Application.WorksheetFunction.CountIf(rng, aNumber) > 0 Then

        rowNum = Application.WorksheetFunction.Match(aNumber, rng, 0)

    Else
        MsgBox aNumber & " does not exist in range " & rng.Address
    End If

End Sub

ALTERNATIVE WAY

Public Sub test()
    Dim rng As Range
    Dim aNumber As Variant
    Dim rowNum As Long

    aNumber = "2gg"

    Set rng = Sheet5.Range("B1:B20")

    If Not IsError(Application.Match(aNumber, rng, 0)) Then
        rowNum = Application.Match(aNumber, rng, 0)
        MsgBox rowNum
    Else
        MsgBox "error"
    End If
End Sub

OR

Public Sub test()
    Dim rng As Range
    Dim aNumber As Variant
    Dim rowNum As Variant

    aNumber = "2gg"

    Set rng = Sheet5.Range("B1:B20")

    rowNum = Application.Match(aNumber, rng, 0)

    If Not IsError(rowNum) Then
        MsgBox rowNum
    Else
        MsgBox "error"
    End If
End Sub