[php] How to download file from database/folder using php

File uploaded will be store in database and folder (folder name: uploads).Now I want to know how to create download file from database/folder. I have two file butangDonload.php and download.php. When user click word "donload" the pop up box will appear and save the file.

butangDonload.php

<?php

    $file = "Bang.png"; //Let say If I put the file name Bang.png
    echo "<a href='download.php?nama=".$file."'>donload</a> ";

?>

download.php

<?php
    $name= $_GET['nama'];
    download($name);

    function download($name) {
        $file = $nama_fail;

        if (file_exists($file)) {
            header('Content-Description: File Transfer');
            header('Content-Type: application/octet-stream');
            header('Content-Disposition: attachment; filename='.basename($file));
            header('Content-Transfer-Encoding: binary');
            header('Expires: 0');
            header('Cache-Control: must-revalidate');
            header('Pragma: public');
            header('Content-Length: ' . filesize($file));
            ob_clean();
            flush();
            readfile($file);
            exit;
        }
    }
?>

You can use html5 tag to download the image directly

<?php
$file = "Bang.png"; //Let say If I put the file name Bang.png
echo "<a href='download.php?nama=".$file."' download>donload</a> ";
?>

For more information, check this link http://www.w3schools.com/tags/att_a_download.asp

butangDonload.php

$file = "Bang.png"; //Let say If I put the file name Bang.png
$_SESSION['name']=$file;    

Try this,

<?php

$name=$_SESSION['name'];
download($name);

function download($name){
$file = $nama_fail;
?>

I have changed to your code with little modification will works well. Here is the code:

butangDonload.php

<?php
$file = "logo_ldg.png"; //Let say If I put the file name Bang.png
echo "<a href='download1.php?nama=".$file."'>download</a> ";
?>

download.php

<?php
$name= $_GET['nama'];

    header('Content-Description: File Transfer');
    header('Content-Type: application/force-download');
    header("Content-Disposition: attachment; filename=\"" . basename($name) . "\";");
    header('Content-Transfer-Encoding: binary');
    header('Expires: 0');
    header('Cache-Control: must-revalidate');
    header('Pragma: public');
    header('Content-Length: ' . filesize($name));
    ob_clean();
    flush();
    readfile("your_file_path/".$name); //showing the path to the server where the file is to be download
    exit;
?>

Here you need to show the path from where the file to be download. i.e. will just give the file name but need to give the file path for reading that file. So, it should be replaced by I have tested by using your code and modifying also will works.

You can also use the following code:

<?php
$filename = $_GET["nama"];
$contenttype = "application/force-download";
header("Content-Type: " . $contenttype);
header("Content-Disposition: attachment; filename=\"" . basename($filename) . "\";");
readfile("your file uploaded path".$filename);
exit();
?>

here is the code to download file with how much % it is downloaded

<?php
$ch = curl_init();
$downloadFile = fopen( 'file name here', 'w' );
curl_setopt($ch, CURLOPT_URL, "file link here");
curl_setopt($ch, CURLOPT_HEADER, 0);
curl_setopt($ch, CURLOPT_BUFFERSIZE, 65536);
curl_setopt($ch, CURLOPT_RETURNTRANSFER, true);
curl_setopt($ch, CURLOPT_FOLLOWLOCATION, true);
curl_setopt($ch, CURLOPT_PROGRESSFUNCTION, 'downloadProgress'); 
curl_setopt($ch, CURLOPT_NOPROGRESS, false);
curl_setopt( $ch, CURLOPT_FILE, $downloadFile );
curl_exec($ch);
curl_close($ch);

function downloadProgress ($resource, $download_size, $downloaded_size, $upload_size, $uploaded_size) {

    if($download_size!=0){
    $percen= (($downloaded_size/$download_size)*100);
    echo $percen."<br>";

}

}
?>