I want a regex for mobile number validation. The regex pattern should be such that it must accept +
only in beginning and space(or -
) should be allowed only after country code(only once). Only 10 digit number should be allowed after the country code. The country code should be optional. If country code doesn't exist, it should accept only 10 digit number. Regex should prevent any invalid number like (eg:+91 0000000000
or 0000000000
).
The regex should accept numbers like
The regex should not accept numbers like
This question is related to
regex
validation
Try this regex:
^(\+?\d{1,4}[\s-])?(?!0+\s+,?$)\d{10}\s*,?$
Explanation of the regex using Perl's YAPE is as below:
NODE EXPLANATION
----------------------------------------------------------------------
(?-imsx: group, but do not capture (case-sensitive)
(with ^ and $ matching normally) (with . not
matching \n) (matching whitespace and #
normally):
----------------------------------------------------------------------
^ the beginning of the string
----------------------------------------------------------------------
( group and capture to \1 (optional
(matching the most amount possible)):
----------------------------------------------------------------------
\+? '+' (optional (matching the most amount
possible))
----------------------------------------------------------------------
\d{1,4} digits (0-9) (between 1 and 4 times
(matching the most amount possible))
----------------------------------------------------------------------
[\s-] any character of: whitespace (\n, \r,
\t, \f, and " "), '-'
----------------------------------------------------------------------
)? end of \1 (NOTE: because you are using a
quantifier on this capture, only the LAST
repetition of the captured pattern will be
stored in \1)
----------------------------------------------------------------------
(?! look ahead to see if there is not:
----------------------------------------------------------------------
0+ '0' (1 or more times (matching the most
amount possible))
----------------------------------------------------------------------
\s+ whitespace (\n, \r, \t, \f, and " ") (1
or more times (matching the most amount
possible))
----------------------------------------------------------------------
,? ',' (optional (matching the most amount
possible))
----------------------------------------------------------------------
$ before an optional \n, and the end of
the string
----------------------------------------------------------------------
) end of look-ahead
----------------------------------------------------------------------
\d{10} digits (0-9) (10 times)
----------------------------------------------------------------------
\s* whitespace (\n, \r, \t, \f, and " ") (0 or
more times (matching the most amount
possible))
----------------------------------------------------------------------
,? ',' (optional (matching the most amount
possible))
----------------------------------------------------------------------
$ before an optional \n, and the end of the
string
----------------------------------------------------------------------
) end of grouping
----------------------------------------------------------------------
This regex is very short and sweet for working.
/^([+]\d{2})?\d{10}$/
Ex: +910123456789 or 0123456789
-> /^ and $/ is for starting and ending
-> The ? mark is used for conditional formatting where before question mark is available or not it will work
-> ([+]\d{2}) this indicates that the + sign with two digits '\d{2}' here you can place digit as per country
-> after the ? mark '\d{10}' this says that the digits must be 10 of length change as per your country mobile number length
This is how this regex for mobile number is working.
+ sign is used for world wide matching of number.
if you want to add the space between than you can use the
[ ]
here the square bracket represents the character sequence and a space is character for searching in regex.
for the space separated digit you can use this regex
/^([+]\d{2}[ ])?\d{10}$/
Ex: +91 0123456789
Thanks ask any question if you have.
Source: Stackoverflow.com