[ios] How to create a string with format?

I need to create a string with format which can convert int, long, double etc. types into string. Using Obj-C, I can do it via below way.

NSString *str = [NSString stringWithFormat:@"%d , %f, %ld, %@", INT_VALUE, FLOAT_VALUE, DOUBLE_VALUE, STRING_VALUE];

How to do same with swift?

First read Official documentation for Swift language.

Answer should be

var str = "\(INT_VALUE) , \(FLOAT_VALUE) , \(DOUBLE_VALUE), \(STRING_VALUE)"
println(str)

Here

1) Any floating point value by default double

EX.
 var myVal = 5.2 // its double by default;

-> If you want to display floating point value then you need to explicitly define such like a

 EX.
     var myVal:Float = 5.2 // now its float value;

This is far more clear.

nothing special

let str = NSString(format:"%d , %f, %ld, %@", INT_VALUE, FLOAT_VALUE, LONG_VALUE, STRING_VALUE)

I know a lot's of time has passed since this publish, but I've fallen in a similar situation and create a simples class to simplify my life.

public struct StringMaskFormatter {

    public var pattern              : String    = ""
    public var replecementChar      : Character = "*"
    public var allowNumbers         : Bool      = true
    public var allowText            : Bool      = false


    public init(pattern:String, replecementChar:Character="*", allowNumbers:Bool=true, allowText:Bool=true)
    {
        self.pattern            = pattern
        self.replecementChar    = replecementChar
        self.allowNumbers       = allowNumbers
        self.allowText          = allowText
    }


    private func prepareString(string:String) -> String {

        var charSet : NSCharacterSet!

        if allowText && allowNumbers {
            charSet = NSCharacterSet.alphanumericCharacterSet().invertedSet
        }
        else if allowText {
            charSet = NSCharacterSet.letterCharacterSet().invertedSet
        }
        else if allowNumbers {
            charSet = NSCharacterSet.decimalDigitCharacterSet().invertedSet
        }

        let result = string.componentsSeparatedByCharactersInSet(charSet)
        return result.joinWithSeparator("")
    }

    public func createFormattedStringFrom(text:String) -> String
    {
        var resultString = ""
        if text.characters.count > 0 && pattern.characters.count > 0
        {

            var finalText   = ""
            var stop        = false
            let tempString  = prepareString(text)

            var formatIndex = pattern.startIndex
            var tempIndex   = tempString.startIndex

            while !stop
            {
                let formattingPatternRange = formatIndex ..< formatIndex.advancedBy(1)

                if pattern.substringWithRange(formattingPatternRange) != String(replecementChar) {
                    finalText = finalText.stringByAppendingString(pattern.substringWithRange(formattingPatternRange))
                }
                else if tempString.characters.count > 0 {
                    let pureStringRange = tempIndex ..< tempIndex.advancedBy(1)
                    finalText = finalText.stringByAppendingString(tempString.substringWithRange(pureStringRange))
                    tempIndex = tempIndex.advancedBy(1)
                }

                formatIndex = formatIndex.advancedBy(1)

                if formatIndex >= pattern.endIndex || tempIndex >= tempString.endIndex {
                    stop = true
                }

                resultString = finalText

            }
        }

        return resultString
    }

}

The follow link send to the complete source code: https://gist.github.com/dedeexe/d9a43894081317e7c418b96d1d081b25

This solution was base on this article: http://vojtastavik.com/2015/03/29/real-time-formatting-in-uitextfield-swift-basics/

The beauty of String(format:) is that you can save a formatting string and then reuse it later in dozen of places. It also can be localized in this single place. Where as in case of the interpolation approach you must write it again and again.

var str = "\(INT_VALUE) , \(FLOAT_VALUE) , \(DOUBLE_VALUE), \(STRING_VALUE)"

There is a simple solution I learned with "We <3 Swift" if you can't either import Foundation, use round() and/or does not want a String:

var number = 31.726354765
var intNumber = Int(number * 1000.0)
var roundedNumber = Double(intNumber) / 1000.0

result: 31.726

Use this following code:

    let intVal=56
    let floatval:Double=56.897898
    let doubleValue=89.0
    let explicitDaouble:Double=89.56
    let stringValue:"Hello"

    let stringValue="String:\(stringValue) Integer:\(intVal) Float:\(floatval) Double:\(doubleValue) ExplicitDouble:\(explicitDaouble) "

Simple functionality is not included in Swift, expected because it's included in other languages, can often be quickly coded for reuse. Pro tip for programmers to create a bag of tricks file that contains all this reuse code.

So from my bag of tricks we first need string multiplication for use in indentation.

@inlinable func * (string: String, scalar: Int) -> String {
    let array = [String](repeating: string, count: scalar)
    return array.joined(separator: "")
}

and then the code to add commas.

extension Int {
    @inlinable var withCommas:String {
        var i = self
        var retValue:[String] = []
        while i >= 1000 {
            retValue.append(String(format:"%03d",i%1000))
            i /= 1000
        }
        retValue.append("\(i)")
        return retValue.reversed().joined(separator: ",")
    }

    @inlinable func withCommas(_ count:Int = 0) -> String {
        let retValue = self.withCommas
        let indentation = count - retValue.count
        let indent:String = indentation >= 0 ? " " * indentation : ""

        return indent + retValue
    }
}

I just wrote this last function so I could get the columns to line up.

The @inlinable is great because it takes small functions and reduces their functionality so they run faster.

You can use either the variable version or, to get a fixed column, use the function version. Lengths set less than the needed columns will just expand the field.

Now you have something that is pure Swift and does not rely on some old objective C routine for NSString.

Success to try it:

 var letters:NSString = "abcdefghijkl"
        var strRendom = NSMutableString.stringWithCapacity(strlength)
        for var i=0; i<strlength; i++ {
            let rndString = Int(arc4random() % 12)
            //let strlk = NSString(format: <#NSString#>, <#CVarArg[]#>)
            let strlk = NSString(format: "%c", letters.characterAtIndex(rndString))
            strRendom.appendString(String(strlk))
        }

I would argue that both

let str = String(format:"%d, %f, %ld", INT_VALUE, FLOAT_VALUE, DOUBLE_VALUE)

and

let str = "\(INT_VALUE), \(FLOAT_VALUE), \(DOUBLE_VALUE)"

are both acceptable since the user asked about formatting and both cases fit what they are asking for:

I need to create a string with format which can convert int, long, double etc. types into string.

Obviously the former allows finer control over the formatting than the latter, but that does not mean the latter is not an acceptable answer.

let INT_VALUE=80
let FLOAT_VALUE:Double= 80.9999
let doubleValue=65.0
let DOUBLE_VALUE:Double= 65.56
let STRING_VALUE="Hello"

let str = NSString(format:"%d , %f, %ld, %@", INT_VALUE, FLOAT_VALUE, DOUBLE_VALUE, STRING_VALUE);
 println(str);

let str = "\(INT_VALUE), \(FLOAT_VALUE), \(DOUBLE_VALUE), \(STRING_VALUE)"

Update: I wrote this answer before Swift had String(format:) added to it's API. Use the method given by the top answer.

No NSString required!

String(format: "Value: %3.2f\tResult: %3.2f", arguments: [2.7, 99.8])

or

String(format:"Value: %3.2f\tResult: %3.2f", 2.7, 99.8)