How do I choose the URL for my Spring Boot webapp

Question

I am using Spring Boot to create a web app  and I am not sure how to change the URL from localhost 8080 to something like localhost 8080 myWebApp    I have a seen a lot of resources online referencing an application properties file and adding that to the classpath  But  I m not sure exactly where to put that    Questions   In my src main resources    How would I assign the URL within the file

User · Answer

As of spring boot 2 the server contextPath property is deprecated  Instead you should use server servlet contextPath   So in your application properties file add   server servlet contextPath  myWebApp  For more details see  https   github com spring-projects spring-boot wiki Spring-Boot-2 0-Migration-Guide servlet-specific-server-properties

User · Answer

You need to set the property server contextPath to  myWebApp   Check out this part of the documentation  The easiest way to set that property would be in the properties file you are using  most likely application properties  but Spring Boot provides a whole lot of different way to set properties  Check out this part of the documentation  EDIT  As has been mentioned by  AbdullahKhan  as of Spring Boot 2 x the property has been deprecated and should be replaced with server servlet contextPath as has been correctly mentioned in this answer

User · Answer

In Spring Boot 2 the property in e g  application properties is server servlet context-path  myWebApp to set the context path  https   docs spring io spring-boot docs 2 0 1 BUILD-SNAPSHOT reference htmlsingle   custom context path

User · Answer

The issue of changing the context path of a Spring application is handled very well in the post titled Spring Boot Change Context Path  Basically the post discusses multiple ways of realizing this viz    Java Config Command Line Arguments Java System Properties OS Environment Variables application properties in Current Directory application properties in the classpath  src main resources or the packaged jar file

User · Answer

In your src main resources put an application properties or application yml and put a server contextPath in there   server contextPath  your context here   When starting your application the application will be available at http   localhost 8080 your context here   For a comprehensive list of properties to set see Appendix A  of the Spring Boot reference guide   Instead of putting it in the application properties you can also pass it as a system property when starting your application  java -jar yourapp jar -Dserver contextPath  your path here

User · Answer

The server contextPath or server context-path works if  in pom xml    packing should be war not jar Add following dependencies   lt dependency gt       lt groupId gt org springframework boot lt  groupId gt        lt artifactId gt spring-boot-starter-web lt  artifactId gt   lt  dependency gt   lt  -- Tomcat TC server -- gt    lt dependency gt        lt groupId gt org springframework boot lt  groupId gt       lt artifactId gt spring-boot-starter-tomcat lt  artifactId gt       lt scope gt provided lt  scope gt    lt  dependency gt    In eclipse  right click on project --  Run as --  Spring Boot App

[url] How do I choose the URL for my Spring Boot webapp?

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