How to declare an array of strings in C

Question

I am trying to iterate over all the elements of a static array of strings in the best possible way  I want to be able to declare it on one line and easily add remove elements from it without having to keep track of the number  Sounds really simple  doesn t it   Possible non-solutions   vector lt string gt  v  v push back  abc    b push back  xyz     for int i   0  i  lt  v size    i        cout  lt  lt  v i   lt  lt  endl    Problems - no way to create the vector on one line with a list of strings  Possible non-solution 2   string list       abc    xyz      Problems - no way to get the number of strings automatically  that I know of    There must be an easy way of doing this

User · Answer

Problems - no way to get the number of strings automatically (that i know of).

There is a bog-standard way of doing this, which lots of people (including MS) define macros like arraysize for:

#define arraysize(ar)  (sizeof(ar) / sizeof(ar[0]))

User · Answer

Here s an example    include  lt iostream gt   include  lt string gt   include  lt vector gt   include  lt iterator gt   int main         const char  const list       zip    zam    bam        const size t len   sizeof list    sizeof list 0         for  size t i   0  i  lt  len    i          std  cout  lt  lt  list i   lt  lt    n        const std  vector lt string gt  v list  list   len       std  copy v begin    v end    std  ostream iterator lt string gt  std  cout    n

User · Answer

You can use Will Dean s suggestion   define arraysize ar    sizeof ar    sizeof ar 0     to replace the magic number 3 here with arraysize str array  -- although I remember there being some special case in which that particular version of arraysize might do Something Bad  sorry I can t remember the details immediately   But it very often works correctly    The case where it doesn t work is when the  array  is really just a pointer  not an actual array  Also  because of the way arrays are passed to functions  converted to a pointer to the first element   it doesn t work across function calls even if the signature looks like an array  mdash  some function string parameter    is really some function string  parameter

User · Answer

C   11 added initialization lists to allow the following syntax   std  vector lt std  string gt  v     Hello    World      Support for this C   11 feature was added in at least GCC 4 4 and only in Visual Studio 2013

User · Answer

You can use the begin and end functions from the Boost range library to easily find the ends of a primitive array  and unlike the macro solution  this will give a compile error instead of broken behaviour if you accidentally apply it to a pointer   const char  array        cat    dog    horse     vector lt string gt  vec begin array   end array

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include  lt iostream gt   include  lt string gt   include  lt vector gt   include  lt boost assign list of hpp gt   int main         const std  vector lt  std  string  gt  v   boost  assign  list of   abc      xyz         std  copy          v begin            v end            std  ostream iterator lt  std  string  gt   std  cout    n

User · Answer

One possiblity is to use a NULL pointer as a flag value   const char  list       dog    cat   NULL   for  char   iList   list   iList    NULL    iList        cout  lt  lt   iList

User · Answer

You can concisely initialize a vector lt string gt  from a statically-created char  array   char  strarray       hey    sup    dogg    vector lt string gt  strvector strarray  strarray   3     This copies all the strings  by the way  so you use twice the memory   You can use Will Dean s suggestion to replace the magic number 3 here with arraysize str array  -- although I remember there being some special case in which that particular version of arraysize might do Something Bad  sorry I can t remember the details immediately    But it very often works correctly   Also  if you re really gung-ho about the one line thingy  you can define a variadic macro so that a single line such as DEFINE STR VEC strvector   hi    there    everyone    works

User · Answer

You can directly declare an array of strings like string s 100    Then if you want to access specific elements  you can get it directly like s 2  90   For iteration purposes  take the size of string using the s i  size   function

User · Answer

include  lt boost foreach hpp gt   const char  list       abc    xyz    BOOST FOREACH const char  str  list        cout  lt  lt  str  lt  lt  endl

User · Answer

Declare an array of strings in C   like this    char array of strings      For example   char array of strings 200  8192    will hold 200 strings  each string having the size 8kb or 8192 bytes   use strcpy line i  tempBuffer    to put data in the array of strings

User · Answer

Instead of that macro  might I suggest this one   template lt typename T  int N gt  inline size t array size T  amp   N         return N      define ARRAY SIZE X     sizeof array size X      sizeof X    sizeof  X  0      -1    1  We want to use a macro to make it a compile-time constant  the function call s result is not a compile-time constant   2  However  we don t want to use a macro because the macro could be accidentally used on a pointer   The function can only be used on compile-time arrays   So  we use the defined-ness of the function to make the macro  safe   if the function exists  i e  it has non-zero size  then we use the macro as above   If the function does not exist we return a bad value

[c++] How to declare an array of strings in C++?

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