How do I remove the file suffix and path portion from a path string in Bash

Question

Given a string file path such as  foo fizzbuzz bar  how would I use bash to extract just the fizzbuzz portion of said string

User · Answer

If you can t use basename as suggested in other posts  you can always use sed  Here is an  ugly  example  It isn t the greatest  but it works by extracting the wanted string and replacing the input with the wanted string   echo   foo fizzbuzz bar    sed  s                          1 g    Which will get you the output          fizzbuzz

User · Answer

The basename and dirname functions are what you re after   mystring  foo fizzbuzz bar echo basename    basename    mystring    echo basename   remove  bar    basename    mystring    bar  echo dirname    dirname    mystring      Has output   basename  fizzbuzz bar basename   remove  bar  fizzbuzz dirname   foo

User · Answer

The basename does that  removes the path   It will also remove the suffix if given and if it matches the suffix of the file but you would need to know the suffix to give to the command  Otherwise you can use mv and figure out what the new name should be some other way

User · Answer

Using basename I used the following to achieve this   for file in    do     ext   file          fname  basename  file  ext         Do things with  fname done    This requires no a priori knowledge of the file extension and works even when you have a filename that has dots in it s filename  in front of it s extension   it does require the program basename though  but this is part of the GNU coreutils so it should ship with any distro

User · Answer

Here s how to do it with the   and   operators in Bash     x   foo fizzbuzz bar    y   x  bar    echo   y      fizzbuzz     x  bar  could also be   x     to remove everything after a dot or   x      to remove everything after the first dot   Example     x   foo fizzbuzz bar quux    y   x       echo  y  foo fizzbuzz bar   y   x        echo  y  foo fizzbuzz   Documentation can be found in the Bash manual  Look for   parameter word  and   parameter  word  trailing portion matching section

User · Answer

The basename does that  removes the path   It will also remove the suffix if given and if it matches the suffix of the file but you would need to know the suffix to give to the command  Otherwise you can use mv and figure out what the new name should be some other way

User · Answer

Beware of the suggested perl solution  it removes anything after the first dot     echo some file with dots   perl -pe  s         s          some   If you want to do it with perl  this works     echo some file with dots   perl -pe  s            1  s          some file with   But if you are using Bash  the solutions with y   x      or basename   x   ext if you know the extension  are much simpler

User · Answer

In addition to the POSIX conformant syntax used in this answer   basename string  suffix   as in  basename  foo fizzbuzz bar  bar   GNU basename supports another syntax   basename -s  bar  foo fizzbuzz bar   with the same result  The difference and advantage is that -s implies -a  which supports multiple arguments     basename -s  bar  foo fizzbuzz bar  baz foobar bar fizzbuzz foobar   This can even be made filename-safe by separating the output with NUL bytes using the -z option  for example for these files containing blanks  newlines and glob characters  quoted by ls      ls has   has    n  newline bar    has space bar    has  bar    Reading into an array     readarray -d    0  arr  lt   lt  basename -zs  bar has     declare -p arr declare -a arr   0    has nnewline   1   has space   2   has      readarray -d requires Bash 4 4 or newer  For older versions  we have to loop   while IFS  read -r -d    fname  do arr     fname    done  lt   lt  basename -zs  bar has

User · Answer

Pure bash way      x   foo bar fizzbuzz bar quux zoom       y   x              echo   y        fizzbuzz   This functionality is explained on man bash under  Parameter Expansion   Non bash ways abound  awk  perl  sed and so on   EDIT  Works with dots in file suffixes and doesn t need to know the suffix  extension   but doesn   t work with dots in the name itself

User · Answer

Using basename assumes that you know what the file extension is  doesn t it   And I believe that the various regular expression suggestions don t cope with a filename containing more than one      The following seems to cope with double dots  Oh  and filenames that contain a     themselves  just for kicks   To paraphrase Pascal   Sorry this script is so long  I didn t have time to make it shorter         usr bin perl    fullname    ARGV 0       path  name     fullname                              basename  extension     name                         print  basename     n

User · Answer

Combining the top-rated answer with the second-top-rated answer to get the filename without the full path      x   foo fizzbuzz bar quux    y   basename   x          echo  y fizzbuzz

User · Answer

Pure bash  done in two separate operations    Remove the path from a path-string   path  foo bar bim baz file gif  file   path          file is now  file gif   Remove the extension from a path-string   base   file        base  is now  file

User · Answer

perl -pe  s         s

User · Answer

look at the basename command  NAME  quot   basename  foo fizzbuzz bar  bar  quot   instructs it to remove the suffix  bar  results in NAME fizzbuzz

[string] How do I remove the file suffix and path portion from a path string in Bash?

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