I wrote a while loop in a function, but don't know how to stop it. When it doesn't meet its final condition, the loop just go for ever. How can I stop it?
def determine_period(universe_array):
period=0
tmp=universe_array
while True:
tmp=apply_rules(tmp)#aplly_rules is a another function
period+=1
if numpy.array_equal(tmp,universe_array) is True:
break #i want the loop to stop and return 0 if the
#period is bigger than 12
if period>12: #i wrote this line to stop it..but seems it
#doesnt work....help..
return 0
else:
return period
This question is related to
python
while-loop
The is operator in Python probably doesn't do what you expect. Instead of this:
if numpy.array_equal(tmp,universe_array) is True:
break
I would write it like this:
if numpy.array_equal(tmp,universe_array):
break
The is operator tests object identity, which is something quite different from equality.
def determine_period(universe_array):
period=0
tmp=universe_array
while period<12:
tmp=apply_rules(tmp)#aplly_rules is a another function
if numpy.array_equal(tmp,universe_array) is True:
break
period+=1
return period
The is operator in Python probably doesn't do what you expect. Instead of this:
if numpy.array_equal(tmp,universe_array) is True:
break
I would write it like this:
if numpy.array_equal(tmp,universe_array):
break
The is operator tests object identity, which is something quite different from equality.
I would do it using a for loop as shown below :
def determine_period(universe_array):
tmp = universe_array
for period in xrange(1, 13):
tmp = apply_rules(tmp)
if numpy.array_equal(tmp, universe_array):
return period
return 0
def determine_period(universe_array):
period=0
tmp=universe_array
while period<12:
tmp=apply_rules(tmp)#aplly_rules is a another function
if numpy.array_equal(tmp,universe_array) is True:
break
period+=1
return period
I would do it using a for loop as shown below :
def determine_period(universe_array):
tmp = universe_array
for period in xrange(1, 13):
tmp = apply_rules(tmp)
if numpy.array_equal(tmp, universe_array):
return period
return 0
The is operator in Python probably doesn't do what you expect. Instead of this:
if numpy.array_equal(tmp,universe_array) is True:
break
I would write it like this:
if numpy.array_equal(tmp,universe_array):
break
The is operator tests object identity, which is something quite different from equality.
I would do it using a for loop as shown below :
def determine_period(universe_array):
tmp = universe_array
for period in xrange(1, 13):
tmp = apply_rules(tmp)
if numpy.array_equal(tmp, universe_array):
return period
return 0
Source: Stackoverflow.com