Java equivalent of unsigned long long

Question

In C    I enjoyed having access to a 64 bit unsigned integer  via unsigned long long int  or via uint64 t  Now  in Java longs are 64 bits  I know  However  they are signed   Is there an unsigned long  long  available as a Java primitive  How do I use it

User · Answer

Depending on the operations you intend to perform  the outcome is much the same  signed or unsigned  However  unless you are using trivial operations you will end up using BigInteger

User · Answer

I don t believe so   Once you want to go bigger than a signed long  I think BigInteger is the only  out of the box  way to go

User · Answer

No  there isn t   The designers of Java are on record as saying they didn t like unsigned ints   Use a BigInteger instead   See this question for details

User · Answer

No  there isn t   The designers of Java are on record as saying they didn t like unsigned ints   Use a BigInteger instead   See this question for details

User · Answer

Java 8 provides a set of unsigned long operations that allows you to directly treat those Long variables as unsigned Long  here re some commonly used ones    String toUnsignedString long i  int compareUnsigned long x  long y  long divideUnsigned long dividend  long divisor  long remainderUnsigned long dividend  long divisor    And additions  subtractions  and multiplications are the same for signed and unsigned longs

User · Answer

For unsigned long you can use UnsignedLong class from Guava library   It supports various operations    plus minus times mod dividedBy   The thing that seems missing at the moment are byte shift operators  If you need those you can use BigInteger from Java

User · Answer

Nope  there is not   You ll have to use the primitive long data type and deal with signedness issues  or use a class such as BigInteger

User · Answer

Java does not have unsigned types  As already mentioned  incure the overhead of BigInteger or use JNI to access native code

User · Answer

Nope  there is not   You ll have to use the primitive long data type and deal with signedness issues  or use a class such as BigInteger

User · Answer

I don t believe so   Once you want to go bigger than a signed long  I think BigInteger is the only  out of the box  way to go

User · Answer

Java 8 provides a set of unsigned long operations that allows you to directly treat those Long variables as unsigned Long  here re some commonly used ones    String toUnsignedString long i  int compareUnsigned long x  long y  long divideUnsigned long dividend  long divisor  long remainderUnsigned long dividend  long divisor    And additions  subtractions  and multiplications are the same for signed and unsigned longs

User · Answer

Starting Java 8  there is support for unsigned long  unsigned 64 bits   The way you can use it is   Long l1   Long parseUnsignedLong  17916881237904312345      To print it  you can not simply print l1  but you have to first   String l1Str   Long toUnsignedString l1    Then  System out println l1Str

User · Answer

Depending on the operations you intend to perform  the outcome is much the same  signed or unsigned  However  unless you are using trivial operations you will end up using BigInteger

User · Answer

For unsigned long you can use UnsignedLong class from Guava library   It supports various operations    plus minus times mod dividedBy   The thing that seems missing at the moment are byte shift operators  If you need those you can use BigInteger from Java

User · Answer

Seems like in Java 8 some methods are added to Long to treat old good  signed  long as unsigned  Seems like a workaround  but may help sometimes

User · Answer

No  there isn t   The designers of Java are on record as saying they didn t like unsigned ints   Use a BigInteger instead   See this question for details

User · Answer

Depending on the operations you intend to perform  the outcome is much the same  signed or unsigned  However  unless you are using trivial operations you will end up using BigInteger

User · Answer

I don t believe so   Once you want to go bigger than a signed long  I think BigInteger is the only  out of the box  way to go

User · Answer

The org apache axis types package has a   UnsignedLong class   for maven    lt dependency gt       lt groupId gt org apache axis lt  groupId gt       lt artifactId gt axis lt  artifactId gt       lt version gt 1 4 lt  version gt   lt  dependency gt

User · Answer

Java does not have unsigned types  As already mentioned  incure the overhead of BigInteger or use JNI to access native code

User · Answer

Java does not have unsigned types  As already mentioned  incure the overhead of BigInteger or use JNI to access native code

User · Answer

Depending on the operations you intend to perform  the outcome is much the same  signed or unsigned  However  unless you are using trivial operations you will end up using BigInteger

User · Answer

Starting Java 8  there is support for unsigned long  unsigned 64 bits   The way you can use it is   Long l1   Long parseUnsignedLong  17916881237904312345      To print it  you can not simply print l1  but you have to first   String l1Str   Long toUnsignedString l1    Then  System out println l1Str

User · Answer

Seems like in Java 8 some methods are added to Long to treat old good  signed  long as unsigned  Seems like a workaround  but may help sometimes

User · Answer

Java does not have unsigned types  As already mentioned  incure the overhead of BigInteger or use JNI to access native code

User · Answer

The org apache axis types package has a   UnsignedLong class   for maven    lt dependency gt       lt groupId gt org apache axis lt  groupId gt       lt artifactId gt axis lt  artifactId gt       lt version gt 1 4 lt  version gt   lt  dependency gt

User · Answer

I don t believe so   Once you want to go bigger than a signed long  I think BigInteger is the only  out of the box  way to go

User · Answer

No  there isn t   The designers of Java are on record as saying they didn t like unsigned ints   Use a BigInteger instead   See this question for details

User · Answer

Nope  there is not   You ll have to use the primitive long data type and deal with signedness issues  or use a class such as BigInteger

User · Answer

Nope  there is not   You ll have to use the primitive long data type and deal with signedness issues  or use a class such as BigInteger

[java] Java equivalent of unsigned long long?

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