[java] How to run Unix shell script from Java code?

Here is an example how to run an Unix bash or Windows bat/cmd script from Java. Arguments can be passed on the script and output received from the script. The method accepts arbitrary number of arguments.

public static void runScript(String path, String... args) {
    try {
        String[] cmd = new String[args.length + 1];
        cmd[0] = path;
        int count = 0;
        for (String s : args) {
            cmd[++count] = args[count - 1];
        }
        Process process = Runtime.getRuntime().exec(cmd);
        BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(process.getInputStream()));
        try {
            process.waitFor();
        } catch (Exception ex) {
            System.out.println(ex.getMessage());
        }
        while (bufferedReader.ready()) {
            System.out.println("Received from script: " + bufferedReader.readLine());
        }
    } catch (Exception ex) {
        System.out.println(ex.getMessage());
        System.exit(1);
    }
}

When running on Unix/Linux, the path must be Unix-like (with '/' as separator), when running on Windows - use '\'. Hier is an example of a bash script (test.sh) that receives arbitrary number of arguments and doubles every argument:

#!/bin/bash
counter=0
while [ $# -gt 0 ]
do
  echo argument $((counter +=1)): $1
  echo doubling argument $((counter)): $(($1+$1))
  shift
done

When calling

runScript("path_to_script/test.sh", "1", "2")

on Unix/Linux, the output is:

Received from script: argument 1: 1
Received from script: doubling argument 1: 2
Received from script: argument 2: 2
Received from script: doubling argument 2: 4

Hier is a simple cmd Windows script test.cmd that counts number of input arguments:

@echo off
set a=0
for %%x in (%*) do Set /A a+=1 
echo %a% arguments received

When calling the script on Windows

  runScript("path_to_script\\test.cmd", "1", "2", "3")

The output is

Received from script: 3 arguments received

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