Use child process execSync but keep output in console

Question

I d like to use the execSync method which was added in NodeJS 0 12 but still have the output in the console window from which i ran the Node script   E g  if I run a NodeJS script which has the following line I d like to see the full output of the rsync command  live  inside the console   require  child process   execSync  rsync -avAXz --info progress2   src    dest       I understand that execSync returns the ouput of the command and that I could print that to the console after execution but this way I don t have  live  output

User · Answer

Simply   try       const cmd    git rev-parse --is-inside-work-tree       execSync cmd  toString       catch  error        console log  Status Code    error status  with    error message         Ref  https   stackoverflow com a 43077917 104085    nodejs var execSync   require  child process   execSync      typescript const   execSync     require  quot child process quot      try       const cmd    git rev-parse --is-inside-work-tree       execSync cmd  toString       catch  error        error status      0   successful exit  but here in exception it has to be greater than 0     error message     Holds the message you typically want      error stderr      Holds the stderr output  Use   toString         error stdout      Holds the stdout output  Use   toString           When command runs successful

User · Answer

You can simply use  toString    var result   require  child process   execSync  rsync -avAXz --info progress2  quot  src quot   quot  dest quot    toString    console log result    This has been tested on Node v8 5 0  I m not sure about previous versions  According to  etov  it doesn t work on v6 3 1 - I m not sure about in-between   Edit  Looking back on this  I ve realised that it doesn t actually answer the specific question because it doesn t show the output to you  live      only once the command has finished running  However  I m leaving this answer here because I know quite a few people come across this question just looking for how to print the result of the command after execution

User · Answer

Unless you redirect stdout and stderr as the accepted answer suggests  this is not possible with execSync or spawnSync   Without redirecting stdout and stderr those commands only return stdout and stderr when the command is completed   To do this without redirecting stdout and stderr  you are going to need to use spawn to do this but it s pretty straight forward   var spawn   require  child process   spawn     kick off process of listing files var child   spawn  ls     -l             spit stdout to screen child stdout on  data   function  data      process stdout write data toString             spit stderr to screen child stderr on  data   function  data      process stdout write data toString           child on  close   function  code         console log  Finished with code     code         I used an ls command that recursively lists files so that you can test it quickly   Spawn takes as first argument the executable name you are trying to run and as it s second argument it takes an array of strings representing each parameter you want to pass to that executable   However  if you are set on using execSync and can t redirect stdout or stderr for some reason  you can open up another terminal like xterm and pass it a command like so   var execSync   require  child process   execSync   execSync  xterm -title RecursiveFileListing -e ls -latkR        This will allow you to see what your command is doing in the new terminal but still have the synchronous call

User · Answer

You can pass the parent  s stdio to the child process if that  s what you want   require  child process   execSync       rsync -avAXz --info progress2   src    dest         stdio   inherit

[node.js] Use child_process.execSync but keep output in console

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