xsl variable Print out value of XSL variable using xsl value-of

Question

I m trying to output a variable s literal string value  after it is being set depending on whether a node exists or not  I think the condition check logic is correct  But it is not outputing the values      lt xsl variable name  subexists   gt    lt xsl template match  class  gt   lt xsl copy gt  lt xsl apply-templates select     node     gt  lt  xsl copy gt   lt xsl choose gt       lt xsl when test  joined-subclass  gt           lt xsl variable name  subexists  select   true    gt       lt  xsl when gt       lt xsl otherwise gt           lt xsl variable name  subexists  select   false    gt       lt  xsl otherwise gt   lt  xsl choose gt  subexists    lt xsl value-of select   subexists    gt      I want it to output the literal string of either  true  of  false   But it is not outputing anything  Please help  Thank you

User · Answer

Your main problem is thinking that the variable you declared outside of the template is the same variable being "set" inside the choose statement. This is not how XSLT works, the variable cannot be reassigned. This is something more like what you want:

<xsl:template match="class">
  <xsl:copy><xsl:apply-templates select="@*|node()"/></xsl:copy>
  <xsl:variable name="subexists">
    <xsl:choose>
      <xsl:when test="joined-subclass">true</xsl:when>
      <xsl:otherwise>false</xsl:otherwise>
    </xsl:choose>
  </xsl:variable>
  subexists:      <xsl:value-of select="$subexists" />
</xsl:template>

And if you need the variable to have "global" scope then declare it outside of the template:

<xsl:variable name="subexists">
  <xsl:choose>
     <xsl:when test="/path/to/node/joined-subclass">true</xsl:when>
     <xsl:otherwise>false</xsl:otherwise>
  </xsl:choose>
</xsl:variable>

<xsl:template match="class">
   subexists:      <xsl:value-of select="$subexists" />
</xsl:template>

User · Answer

In XSLT the same  lt xsl variable gt  can be declared only once and can be given a value only at its declaration  If more than one variables are declared at the same time  they are in fact different variables and have different scope   Therefore  the way to achieve the wanted conditional setting of the variable and producing its value is the following    lt xsl stylesheet version  1 0   xmlns xsl  http   www w3 org 1999 XSL Transform  gt    lt xsl output omit-xml-declaration  yes   gt        lt xsl template match  class  gt       lt xsl variable name  subexists  gt               lt xsl choose gt                   lt xsl when test  joined-subclass  gt true lt  xsl when gt                   lt xsl otherwise gt false lt  xsl otherwise gt               lt  xsl choose gt           lt  xsl variable gt          subexists    lt xsl text  gt               lt xsl value-of select   subexists    gt       lt  xsl template gt   lt  xsl stylesheet gt    When the above transformation is applied on the following XML document    lt class gt    lt joined-subclass  gt   lt  class gt    the wanted result is produced       subexists   true

User · Answer

In this case no conditionals are needed to set the variable   This one-liner XPath expression   boolean joined-subclass    is true   only when the child of the current node   named joined-subclass exists and it is false   otherwise   The complete stylesheet is    lt xsl stylesheet version  1 0   xmlns xsl  http   www w3 org 1999 XSL Transform  gt    lt xsl output omit-xml-declaration  yes   gt     lt xsl template match  class  gt      lt xsl variable name  subexists          select  boolean joined-subclass        gt      subexists    lt xsl text  gt      lt xsl value-of select   subexists    gt    lt  xsl template gt   lt  xsl stylesheet gt    Do note  that the use of the XPath function boolean   in this expression is to convert a node  or its absense  to one of the boolean values true   or false

[xslt] <xsl:variable> Print out value of XSL variable using <xsl:value-of>

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