[bash] How to escape single quotes within single quoted strings

I always just replace each embedded single quote with the sequence: '\'' (that is: quote backslash quote quote) which closes the string, appends an escaped single quote and reopens the string.


I often whip up a "quotify" function in my Perl scripts to do this for me. The steps would be:

s/'/'\\''/g    # Handle each embedded quote
$_ = qq['$_']; # Surround result with single quotes.

This pretty much takes care of all cases.

Life gets more fun when you introduce eval into your shell-scripts. You essentially have to re-quotify everything again!

For example, create a Perl script called quotify containing the above statements:

#!/usr/bin/perl -pl
s/'/'\\''/g;
$_ = qq['$_'];

then use it to generate a correctly-quoted string:

$ quotify
urxvt -fg '#111111' -bg '#111111'

result:

'urxvt -fg '\''#111111'\'' -bg '\''#111111'\'''

which can then be copy/pasted into the alias command:

alias rxvt='urxvt -fg '\''#111111'\'' -bg '\''#111111'\'''

(If you need to insert the command into an eval, run the quotify again:

 $ quotify
 alias rxvt='urxvt -fg '\''#111111'\'' -bg '\''#111111'\'''

result:

'alias rxvt='\''urxvt -fg '\''\'\'''\''#111111'\''\'\'''\'' -bg '\''\'\'''\''#111111'\''\'\'''\'''\'''

which can be copy/pasted into an eval:

eval 'alias rxvt='\''urxvt -fg '\''\'\'''\''#111111'\''\'\'''\'' -bg '\''\'\'''\''#111111'\''\'\'''\'''\'''