double randDouble()
{
double out;
out = (double)rand()/(RAND_MAX + 1); //each iteration produces a number in [0, 1)
out = (rand() + out)/RAND_MAX;
out = (rand() + out)/RAND_MAX;
out = (rand() + out)/RAND_MAX;
out = (rand() + out)/RAND_MAX;
out = (rand() + out)/RAND_MAX;
return out;
}
Not quite as fast as double X=((double)rand()/(double)RAND_MAX);
, but with better distribution. That algorithm gives only RAND_MAX evenly spaced choice of return values; this one gives RANDMAX^6, so its distribution is limited only by the precision of double.
If you want a long double just add a few iterations. If you want a number in [0, 1] rather than [0, 1) just make line 4 read out = (double)rand()/(RAND_MAX);
.