I have the following line:
hshd household 8/29/2007 LB
I want to match anything that comes before the first space (whitespace). So, in this case, I want to get back
hshd
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regex
This should do it:
^\S*
I think, that will be good solution: /\S\w*/
Perhaps you could try ([^ ]+) .*
, which should give you everything to the first blank in your first group.
for the entire line
^(\w+)\s+(\w+)\s+(\d+(?:\/\d+){2})\s+(\w+)$
^([^\s]+) use this it correctly matches only the first word you can test this using this link https://regex101.com/
Derived from the answer of @SilentGhost I would use:
^([\S]+)
Check out this interactive regexr.com page to see the result and explanation for the suggested solution.
I think, a word was created with more than one letters. My suggestion is:
[^\s\s$]{2,}
Source: Stackoverflow.com