Java Finding the highest value in an array

Question

For some reason this code is printing three values for the highest value in the array when I m trying to print just one  which is 11 3   Can someone please explain to me why it is doing this   Thanks   import java util Scanner   public class Slide24       public static void main  String    args                Scanner in   new Scanner System in            double   decMax    -2 8  -8 8  2 3  7 9  4 1  -1 4  11 3  10 4              8 9  8 1  5 8  5 9  7 8  4 9  5 7  -0 9  -0 4  7 3  8 3  6 5  9 2              3 5  3  1 1  6 5  5 1  -1 2  -5 1  2  5 2  2 1            double total   0  avgMax   0           for  int counter   0  counter  lt  decMax length  counter                       total    decMax counter                      avgMax   total   decMax length           System out printf   s  2 2f n    The average maximum temperature for December was     avgMax              finds the highest value         double max   decMax 0            for  int counter   1  counter  lt  decMax length  counter                       if  decMax counter   gt  max                       max   decMax counter             System out println  The highest maximum for the December is      max

User · Answer

A shorter solution to have the max value of array   double max   Arrays stream decMax  max Double  compareTo  get

User · Answer

You are just Compare zeroth element with rest of the elements so it will print the value last largest value which it will contain  in you case  same problem is happening  To compare each and every elements we have to swap the values like   double max   decMax 0       for  int counter   1  counter  lt  decMax length  counter             if max lt decMax i                max decMax i     swapping             decMax i  decMax 0                       System out println  The max value is    max     Hope this will help you

User · Answer

You need to print out the max after you ve scanned all of them   for  int counter   1  counter  lt  decMax length  counter          if  decMax counter   gt  max                max   decMax counter              not here  System out println  The highest maximum for the December is      max             System out println  The highest maximum for the December is      max

User · Answer

If you don t want to use any java predefined libraries then below is the   simplest way     public class Test        public static void main String   args            double   decMax    -2 8  -8 8  2 3  7 9  4 1  -1 4  11 3  10 4              8 9  8 1  5 8  5 9  7 8  4 9  5 7  -0 9  -0 4  7 3  8 3  6 5  9 2              3 5  3  1 1  6 5  5 1  -1 2  -5 1  2  5 2  2 1            double maxx   decMax 0            for  int i   0  i  lt  decMax length  i                  if  maxx  lt  decMax i                     maxx   decMax i                                   System out println maxx

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import java util    class main9   Find the smallest and 2lagest and  ascending and descending order of  elements in array         public static void main String args                  Scanner sc new Scanner System in           System out println  Enter the array range            int no sc nextInt            System out println  Enter the array element            int a   new int no           int i          for i 0 i lt no i                          a i  sc nextInt                      Arrays sort a           int s a 0           int l a a length-1           int m a a length-2           System out println  Smallest no is   s           System out println  lagest 2 numbers are             System out println l           System out println m           System out println  Array in ascending             for i 0 i lt no i                          System out println a i                      System out println  Array in descending             for i a length-1 i gt  0 i--                        System out println a i

User · Answer

Same as suggested by others  just mentioning the cleaner way of doing it   int max   decMax 0   for int i 1 i lt decMax length i        max   Math max decMax i  max   System out println  The Maximum value is       max

User · Answer

Easiest way which I ve found  supports all android versions  Arrays sort series1Numbers    int maxSeries   Integer parseInt String valueOf series1Numbers series1Numbers length-1

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You can use a function that accepts a array and finds the max value in it  i made it generic so it could also accept other data types  public static  lt T extends Comparable lt T gt  gt  T findMax T   array              T max   array 0       for T data  array           if data compareTo max  gt 0              max  data                            return max

User · Answer

You have your print   statement in the for   loop  It should be after so that it only prints once  the way it currently is  every time the max changes it prints a max

User · Answer

You can write like this    import java util Scanner  class   BigNoArray       public static void main String   args           Scanner sc   new Scanner System in           System out println  Enter how many array element            int n sc nextInt            int   ar  new int n           System out println  enter   n   values            for int i 0 i lt ar length i                 ar i  sc nextInt                      int fbig ar 0           int sbig ar 1           int tbig ar 3               for int i 1 i lt ar length i                     if fbig lt ar i                        sbig fbig                      fbig ar i                                     else if sbig lt ar i  amp  amp ar i   fbig                       sbig ar i                                     else if tbig lt ar i  amp  amp ar i   fbig                       tbig ar i                                           System out println  first big number is   fbig           System out println  second big number is   sbig           System out println  third big number is   tbig

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void FindMax         int lessonNum       System out print  Enter your lesson numbers           lessonNum   input nextInt        int   numbers   new int lessonNum       for  int i   0  i  lt  numbers length  i                  System out print  Please enter      i   1      number               numbers i    input nextInt              double max   numbers 0       for  int i   1  i  lt  numbers length  i                  if  numbers i   gt  max                        max   numbers i                       System out println  Maximum number is       max

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To find the highest  max  or lowest  min  value from an array  this could give you the right direction  Here is an example code for getting the highest value from a primitive array  Method 1  public int maxValue int array       List lt Integer gt  list   new ArrayList lt Integer gt       for  int i   0  i  lt  array length  i          list add array i         return Collections max list      To get the lowest value  you can use Collections min list  Method 2  public int maxValue int array       int max   Arrays stream array  max   getAsInt      return max     Now the following line should work  System out println  The highest maximum for the December is      maxValue decMax

User · Answer

If you are looking for the quickest and simplest way to perform various actions in regards to arrays  the use of the Collections class is extremely helpful  documentation available from https   docs oracle com javase 7 docs api java util Collections html   actions ranges from finding the maximum  minimum  sorting  reverse order  etc   A simple way to find the maximum value from the array with the use of Collections   Double   decMax    -2 8  -8 8  2 3  7 9  4 1  -1 4  11 3  10 4  8 9  8 1  5 8  5 9  7 8  4 9  5 7  -0 9  -0 4  7 3  8 3  6 5  9 2  3 5  3 0  1 1  6 5  5 1  -1 2  -5 1  2 0  5 2  2 1   List lt Double gt  a   new ArrayList lt Double gt  Arrays asList decMax    System out println  The highest maximum for the December is      Collections max a      If you are interested in finding the minimum value  similar to finding maximum   System out println Collections min a      The simplest line to sort the list   Collections sort a     Or alternatively the use of the Arrays class to sort an array   Arrays sort decMax     However the Arrays class does not have a method that refers to the maximum value directly  sorting it and referring to the last index is the maximum value  however keep in mind sorting by the above 2 methods has a complexity of O n log n

User · Answer

It s printing out a number every time it finds one that is higher than the current max  which happens to occur three times in your case   Move the print outside of the for loop and you should be good   for  int counter   1  counter  lt  decMax length  counter           if  decMax counter   gt  max               max   decMax counter             System out println  The highest maximum for the December is      max

User · Answer

An easy way without using collections  public void findHighestNoInArray             int   a    1 2 6 8 9           int large   a 0               for int num   a                    if large  lt  num                        large   num                                              System out println  Large number is   large

[java] Java: Finding the highest value in an array

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