I am a little confused about how this code works:
fig, axes = plt.subplots(nrows=2, ncols=2)
plt.show()
How does the fig, axes work in this case? What does it do?
Also why wouldn't this work to do the same thing:
fig = plt.figure()
axes = fig.subplots(nrows=2, ncols=2)
This question is related to
python
matplotlib
subplot
Go with the following if you really want to use a loop. Nobody has actually answered how to feed data in a loop:
def plot(data):
fig = plt.figure(figsize=(100, 100))
for idx, k in enumerate(data.keys(), 1):
x, y = data[k].keys(), data[k].values
plt.subplot(63, 10, idx)
plt.bar(x, y)
plt.show()
read the documentation: matplotlib.pyplot.subplots
pyplot.subplots()
returns a tuple fig, ax
which is unpacked in two variables using the notation
fig, axes = plt.subplots(nrows=2, ncols=2)
the code
fig = plt.figure()
axes = fig.subplots(nrows=2, ncols=2)
does not work because subplots()
is a function in pyplot
not a member of the object Figure
.
You might be interested in the fact that as of matplotlib version 2.1 the second code from the question works fine as well.
From the change log:
Figure class now has subplots method The Figure class now has a subplots() method which behaves the same as pyplot.subplots() but on an existing figure.
Example:
import matplotlib.pyplot as plt
fig = plt.figure()
axes = fig.subplots(nrows=2, ncols=2)
plt.show()
You can also unpack the axes in the subplots call
And set whether you want to share the x and y axes between the subplots
Like this:
import matplotlib.pyplot as plt
fig, ((ax1, ax2), (ax3, ax4)) = plt.subplots(nrows=2, ncols=2, sharex=True, sharey=True)
ax1.plot(range(10), 'r')
ax2.plot(range(10), 'b')
ax3.plot(range(10), 'g')
ax4.plot(range(10), 'k')
plt.show()
Iterating through all subplots sequentially:
fig, axes = plt.subplots(nrows, ncols)
for ax in axes.flatten():
ax.plot(x,y)
Accessing a specific index:
for row in range(nrows):
for col in range(ncols):
axes[row,col].plot(x[row], y[col])
Source: Stackoverflow.com