I'm having trouble after looking at the jQuery docs. I'm just trying to return true/false in one my my jquery methods depending on the check of a certain radiobutton and if it's selected or not
I've tried several things but have not been able to get this right:
<input type="radio" runat="server" name="testGroup" id="test1" /><label for="<%=test1.ClientID %>" style="cursor:hand" runat="server">Test1</label>
<input type="radio" runat="server" name="testGroup" id="test2" /><label for="<%=test2.ClientID %>" style="cursor:hand" runat="server">Test2</label>
<input type="radio" runat="server" name="testGroup" id="test3" /> <label for="<%=test3.ClientID %>" style="cursor:hand">Test3</label>
and in my method I have this:
return $("input[@name='test2']:checked");
I'm getting an undefined on $("input[@name='test2']:checked");
UPDATED:
example:
<input type="radio" runat="server" name="radioGroup" id="payPalRadioButton" value="paypalSelected" />
this returns 'undefined' still:
$("input[@name=radioGroup]:checked").attr('payPalRadioButton');
If I try this, I get 'false' even if I select the radio button:
$('input:radio[name=radioGroup]:checked').val() == 'paypalSelected'
This question is related to
jquery
radio-button
Just found a proper working solution for other guys,
// Returns true or false based on the radio button checked_x000D_
$('#test1').prop('checked')_x000D_
_x000D_
_x000D_
$('body').on('change','input[type="radio"]',function () {_x000D_
alert('Test1 checked = ' + $('#test1').prop('checked') + '. Test2 checked = ' + $('#test2').prop('checked') + '. Test3 checked = ' + $('#test3').prop('checked'));_x000D_
});
_x000D_
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>_x000D_
_x000D_
<input type="radio" runat="server" name="testGroup" id="test1" /><label for="<%=test1.ClientID %>" style="cursor:hand" runat="server">Test1</label>_x000D_
_x000D_
<input type="radio" runat="server" name="testGroup" id="test2" /><label for="<%=test2.ClientID %>" style="cursor:hand" runat="server">Test2</label>_x000D_
_x000D_
<input type="radio" runat="server" name="testGroup" id="test3" /> <label for="<%=test3.ClientID %>" style="cursor:hand">Test3</label>
_x000D_
and in your method you can use like
return $('#test2').prop('checked');
You should remove the '@' before 'name'; it's not needed anymore (for current jQuery versions).
You're want to return all checked elements with name 'test2', but you don't have any elements with that name, you're using an id of 'test2'.
If you're going to use IDs, just try:
return $('#test2').attr('checked');
I think you're using the wrong approach. You should set the value
attribute of your input elements. Check the docs for .val() for examples of setting and returning the .val() of input elements.
ie.
<input type="radio" runat="server" name="testGroup" value="test2" />
return $('input:radio[name=testGroup]:checked').val() == 'test2';
$("input[@name='<%=test2.ClientID%>']:checked");
use this and here ClientID fetch random id created by .net.
WHy bother with all of the fancy selectors? If you're using those id="" attributes properly, then 'test2' must be the only tag with that id on the page, then the .checked boolean property will tell you if it's checked or not:
if ($('test2').checked) {
....
}
You've also not set any values for those radio buttons, so no matter which button you select, you'll just get a blank "testGroup=" submitted to the server.
1.You don't need the @
prefix for attribute names any more:
http://api.jquery.com/category/selectors/attribute-selectors/:
Note: In jQuery 1.3 [@attr] style selectors were removed (they were previously deprecated in jQuery 1.2). Simply remove the ‘@’ symbol from your selectors in order to make them work again.
2.Your selector queries radio buttons by name
, but that attribute is not defined in your HTML structure.
Source: Stackoverflow.com