this
does not affect resulting code - it is compilation time operator and the code generated with or without it will be the same. When you have to use it, depends on context. For example you have to use it, as you said, when you have local variable that shadows class variable and you want refer to class variable and not local one.
edit: by "resulting code will be the same" I mean of course, when some variable in local scope doesn't hide the one belonging to class. Thus
class POJO {
protected int i;
public void modify() {
i = 9;
}
public void thisModify() {
this.i = 9;
}
}
resulting code of both methods will be the same. The difference will be if some method declares local variable with the same name
public void m() {
int i;
i = 9; // i refers to variable in method's scope
this.i = 9; // i refers to class variable
}