Extract directory path and filename

Question

I have a variable which has the directory path  along with the file name  I want to extract the filename alone from the Unix directory path and store it in a variable   fspec   exp home1 abc txt

User · Answer

echo  fspec   tr       n  tail -1

User · Answer

You can simply do   base   basename   fspec

User · Answer

bash   fspec   exp home1 abc txt  fname    fspec

User · Answer

bash to get file name  fspec   exp home1 abc txt   filename    fspec          get filename dirname    fspec        get directory path name   other ways   awk    echo  fspec   awk -F      print  NF   abc txt   sed    echo  fspec   sed  s         abc txt   using IFS    IFS       set --  fspec   eval echo           abc txt

User · Answer

Using bash  here string      fspec   exp home1 abc txt     tr         n    lt  lt  lt   fspec   tail -1 abc txt   filename   tr         n    lt  lt  lt   fspec   tail -1    echo  filename abc txt   The benefit of the  here string  is that it avoids the need overhead of running an echo command  In other words  the  here string  is internal to the shell  That is     tr  lt  lt  lt   fspec   as opposed to     echo  fspec   tr

User · Answer

dirname   usr home theconjuring music song mp3  will yield      usr home theconjuring music

User · Answer

Use the basename command to extract the filename from the path     tmp   export fspec  exp home1 abc txt    tmp   fname  basename  fspec    tmp   echo  fname abc txt

[shell] Extract directory path and filename

Examples related to shell

Examples related to unix