I am not a regex expert, but my request is simple: I need to match any string that has at least 3 or more characters that are matching.
So for instance, we have the string "hello world" and matching it with the following:
"he" => false // only 2 characters
"hel" => true // 3 characters match found
This question is related to
regex
If you want to match starting from the beginning of the word, use:
\b\w{3,}
\b: word boundary
\w: word character
{3,}: three or more times for the word character
For .NET usage:
\p{L}{3,}
Try this .{3,} this will match any characher except new line (\n)
This is python regex, but it probably works in other languages that implement it, too.
I guess it depends on what you consider a character to be. If it's letters, numbers, and underscores:
\w{3,}
if just letters and digits:
[a-zA-Z0-9]{3,}
Python also has a regex method to return all matches from a string.
>>> import re
>>> re.findall(r'\w{3,}', 'This is a long string, yes it is.')
['This', 'long', 'string', 'yes']
I tried find similiar as topic first post.
For my needs I find this
http://answers.oreilly.com/topic/217-how-to-match-whole-words-with-a-regular-expression/
"\b[a-zA-Z0-9]{3}\b"
3 char words only "iokldöajf asd alkjwnkmd asd kja wwda da aij ednm <.jkakla "
You could try with simple 3 dots. refer to the code in perl below
$a =~ m /.../ #where $a is your string
Source: Stackoverflow.com