I'm trying to use JS to turn a date object
into a string in YYYYMMDD
format. Is there an easier way than concatenating Date.getYear()
, Date.getMonth()
, and Date.getDay()
?
This question is related to
javascript
date
date-formatting
You can create yourself function as below
function toString(o, regex) {
try {
if (!o) return '';
if (typeof o.getMonth === 'function' && !!regex) {
let splitChar = regex.indexOf('/') > -1 ? '/' : regex.indexOf('-') > -1 ? '-' : regex.indexOf('.') > -1 ? '.' : '';
let dateSeparate = regex.split(splitChar);
let result = '';
for (let item of dateSeparate) {
let val = '';
switch (item) {
case 'd':
val = o.getDate();
break;
case 'dd':
val = this.date2Char(o.getDate());
break;
case 'M':
val = o.getMonth() + 1;
break;
case 'MM':
val = this.date2Char(o.getMonth() + 1);
break;
case 'yyyy':
val = o.getFullYear();
break;
case 'yy':
val = this.date2Char(o.getFullYear());
break;
default:
break;
}
result += val + splitChar;
}
return result.substring(0, result.length - 1);
} else {
return o.toString();
}
} catch(ex) { return ''; }
}
function concatDateToString(args) {
if (!args.length) return '';
let result = '';
for (let i = 1; i < args.length; i++) {
result += args[i] + args[0];
}
return result.substring(0, result.length - 1);
}
function date2Char(d){
return this.rightString('0' + d);
}
function rightString(o) {
return o.substr(o.length - 2);
}
Used:
var a = new Date();
console.log('dd/MM/yyyy: ' + toString(a, 'dd/MM/yyyy'));
console.log('MM/dd/yyyy: ' + toString(a, 'MM/dd/yyyy'));
console.log('dd/MM/yy: ' + toString(a, 'dd/MM/yy'));
console.log('MM/dd/yy: ' + toString(a, 'MM/dd/yy'));
From ES6 onwards you can use template strings to make it a little shorter:
var now = new Date();
var todayString = `${now.getFullYear()}-${now.getMonth()}-${now.getDate()}`;
This solution does not zero pad. Look to the other good answers to see how to do that.
Date.js has a lot of helpful date parsing methods.
require("datejs")
(new Date()).toString("yyyyMMdd")
Nice, and easy:
var date = new Date();
var yyyy = date.getFullYear();
var mm = date.getMonth() + 1; // getMonth() is zero-based
if (mm < 10) mm='0'+mm;
var dd = date.getDate();
if (dd < 10) dd='0'+dd;
/*date.yyyymmdd();*/
console.log('test - '+yyyy+'-'+mm+'-'+dd);
Little bit simplified version for the most popular answer in this thread https://stackoverflow.com/a/3067896/5437379 :
function toYYYYMMDD(d) {
var yyyy = d.getFullYear().toString();
var mm = (d.getMonth() + 101).toString().slice(-2);
var dd = (d.getDate() + 100).toString().slice(-2);
return yyyy + mm + dd;
}
yyyymmdd=x=>(f=x=>(x<10&&'0')+x,x.getFullYear()+f(x.getMonth()+1)+f(x.getDate()));_x000D_
alert(yyyymmdd(new Date));
_x000D_
new Date('Jun 5 2016').
toLocaleString('en-us', {year: 'numeric', month: '2-digit', day: '2-digit'}).
replace(/(\d+)\/(\d+)\/(\d+)/, '$3-$1-$2');
// => '2016-06-05'
var dateDisplay = new Date( 2016-11-09 05:27:00 UTC );
dateDisplay = dateDisplay.toString()
var arr = (dateDisplay.split(' '))
var date_String = arr[0]+','+arr[1]+' '+arr[2]+' '+arr[3]+','+arr[4]
this will show string like Wed,Nov 09 2016,10:57:00
If using AngularJs (up to 1.5) you can use the date filter:
var formattedDate = $filter('date')(myDate, 'yyyyMMdd')
To get the local date, in a YYYYMMDD format, im using:
var todayDate = (new Date()).toLocaleString('en-GB').slice(0,10).split("\/").reverse().join("");
Native Javascript:
new Date().toLocaleString('zu-ZA').slice(0,10).replace(/-/g,'');
this post helped me to write this helper, so I share it in case some one is looking for this solution, it supports all variations of yyyy, mm, dd
Date.prototype.formattedDate = function (pattern) {
formattedDate = pattern.replace('yyyy', this.getFullYear().toString());
var mm = (this.getMonth() + 1).toString(); // getMonth() is zero-based
mm = mm.length > 1 ? mm : '0' + mm;
formattedDate = formattedDate.replace('mm', mm);
var dd = this.getDate().toString();
dd = dd.length > 1 ? dd : '0' + dd;
formattedDate = formattedDate.replace('dd', dd);
return formattedDate;
};
d = new Date();
pattern = 'yyyymmdd'; // 20150813
d.formattedDate(pattern);
pattern = 'yyyy-mm-dd';
d.formattedDate(pattern); // 2015-08-13
Here's a compact little function that's easy to read and avoids local variables, which can be time-sinks in JavaScript. I don't use prototypes to alter standard modules, because it pollutes the namespace and can lead to code that doesn't do what you think it should.
The main function has a stupid name, but it gets the idea across.
function dateToYYYYMMDDhhmmss(date) {
function pad(num) {
num = num + '';
return num.length < 2 ? '0' + num : num;
}
return date.getFullYear() + '/' +
pad(date.getMonth() + 1) + '/' +
pad(date.getDate()) + ' ' +
pad(date.getHours()) + ':' +
pad(date.getMinutes()) + ':' +
pad(date.getSeconds());
}
<pre>Date.prototype.getFromFormat = function(format) {
var yyyy = this.getFullYear().toString();
format = format.replace(/yyyy/g, yyyy)
var mm = (this.getMonth()+1).toString();
format = format.replace(/mm/g, (mm[1]?mm:"0"+mm[0]));
var dd = this.getDate().toString();
format = format.replace(/dd/g, (dd[1]?dd:"0"+dd[0]));
var hh = this.getHours().toString();
format = format.replace(/hh/g, (hh[1]?hh:"0"+hh[0]));
var ii = this.getMinutes().toString();
format = format.replace(/ii/g, (ii[1]?ii:"0"+ii[0]));
var ss = this.getSeconds().toString();
format = format.replace(/ss/g, (ss[1]?ss:"0"+ss[0]));
var ampm = (hh >= 12) ? "PM" : "AM";
format = format.replace(/ampm/g, (ampm[1]?ampm:"0"+ampm[0]));
return format;
};
var time_var = $('#899_TIME');
var myVar = setInterval(myTimer, 1000);
function myTimer() {
var d = new Date();
var date = d.getFromFormat('dd-mm-yyyy hh:ii:ss:ampm');
time_var.text(date);
} </pre>
use the code and get the output like **26-07-2017 12:29:34:PM**
check the below link for your reference
https://parthiban037.wordpress.com/2017/07/26/date-and-time-format-in-oracle-apex-using-javascript/
date-shortcode to the rescue!
const dateShortcode = require('date-shortcode')
dateShortcode.parse('{YYYYMMDD}', new Date())
//=> '20180304'
[day,,month,,year]= Intl.DateTimeFormat(undefined, { year: 'numeric', month: '2-digit', day: '2-digit' }).formatToParts(new Date()),year.value+month.value+day.value
or
new Date().toJSON().slice(0,10).replace(/\/|-/g,'')
dateformat is a very used package.
How to use:
Download and install dateformat
from NPM. Require it in your module:
const dateFormat = require('dateformat');
and then just format your stuff:
const myYYYYmmddDate = dateformat(new Date(), 'yyyy-mm-dd');
In addition to o-o's answer I'd like to recommend separating logic operations from the return and put them as ternaries in the variables instead.
Also, use concat()
to ensure safe concatenation of variables
Date.prototype.yyyymmdd = function() {_x000D_
var yyyy = this.getFullYear();_x000D_
var mm = this.getMonth() < 9 ? "0" + (this.getMonth() + 1) : (this.getMonth() + 1); // getMonth() is zero-based_x000D_
var dd = this.getDate() < 10 ? "0" + this.getDate() : this.getDate();_x000D_
return "".concat(yyyy).concat(mm).concat(dd);_x000D_
};_x000D_
_x000D_
Date.prototype.yyyymmddhhmm = function() {_x000D_
var yyyymmdd = this.yyyymmdd();_x000D_
var hh = this.getHours() < 10 ? "0" + this.getHours() : this.getHours();_x000D_
var min = this.getMinutes() < 10 ? "0" + this.getMinutes() : this.getMinutes();_x000D_
return "".concat(yyyymmdd).concat(hh).concat(min);_x000D_
};_x000D_
_x000D_
Date.prototype.yyyymmddhhmmss = function() {_x000D_
var yyyymmddhhmm = this.yyyymmddhhmm();_x000D_
var ss = this.getSeconds() < 10 ? "0" + this.getSeconds() : this.getSeconds();_x000D_
return "".concat(yyyymmddhhmm).concat(ss);_x000D_
};_x000D_
_x000D_
var d = new Date();_x000D_
document.getElementById("a").innerHTML = d.yyyymmdd();_x000D_
document.getElementById("b").innerHTML = d.yyyymmddhhmm();_x000D_
document.getElementById("c").innerHTML = d.yyyymmddhhmmss();
_x000D_
<div>_x000D_
yyyymmdd: <span id="a"></span>_x000D_
</div>_x000D_
<div>_x000D_
yyyymmddhhmm: <span id="b"></span>_x000D_
</div>_x000D_
<div>_x000D_
yyyymmddhhmmss: <span id="c"></span>_x000D_
</div>
_x000D_
If you don't need a pure JS solution, you can use jQuery UI to do the job like this :
$.datepicker.formatDate('yymmdd', new Date());
I usually don't like to import too much libraries. But jQuery UI is so useful, you will probably use it somewhere else in your project.
Visit http://api.jqueryui.com/datepicker/ for more examples
Local time:
var date = new Date();
date = date.toJSON().slice(0, 10);
UTC time:
var date = new Date().toISOString();
date = date.substring(0, 10);
date will print 2020-06-15 today as i write this.
toISOString() method returns the date with the ISO standard which is YYYY-MM-DDTHH:mm:ss.sssZ
The code takes the first 10 characters that we need for a YYYY-MM-DD format.
If you want format without '-' use:
var date = new Date();
date = date.toJSON().slice(0, 10).split`-`.join``;
In .join`` you can add space, dots or whatever you'd like.
This code is fix to Pierre Guilbert's answer:
(it works even after 10000 years)
YYYYMMDD=new Date().toISOString().slice(0,new Date().toISOString().indexOf("T")).replace(/-/g,"")
This is a single line of code that you can use to create a YYYY-MM-DD
string of today's date.
var d = new Date().toISOString().slice(0,10);
This guy here => http://blog.stevenlevithan.com/archives/date-time-format wrote a format()
function for the Javascript's Date
object, so it can be used with familiar literal formats.
If you need full featured Date formatting in your app's Javascript, use it. Otherwise if what you want to do is a one off, then concatenating getYear(), getMonth(), getDay() is probably easiest.
.toJSON().slice(0,10).split`-`.join``;
let d = new Date();
let s = d.toJSON().slice(0,10).split`-`.join``;
console.log(s);
_x000D_
Here is a little improvement to the answer from https://stackoverflow.com/users/318563/o-o
Date.prototype.ddmmyyyy = function(delimiter) {
var yyyy = this.getFullYear().toString();
var mm = (this.getMonth()+1).toString(); // getMonth() is zero-based
var dd = this.getDate().toString();
return (dd[1]?dd:"0"+dd[0]) + delimiter + (mm[1]?mm:"0"+mm[0]) + delimiter +yyyy ; // padding
};
Hope to be helpfull for anyone!
:)
Try this:
function showdate(){
var a = new Date();
var b = a.getFullYear();
var c = a.getMonth();
(++c < 10)? c = "0" + c : c;
var d = a.getDate();
(d < 10)? d = "0" + d : d;
var final = b + "-" + c + "-" + d;
return final;
}
document.getElementById("todays_date").innerHTML = showdate();
var someDate = new Date();_x000D_
var dateFormated = someDate.toISOString().substr(0,10);_x000D_
_x000D_
console.log(dateFormated);
_x000D_
You can simply use This one line code to get date in year
var date = new Date().getFullYear() + "-" + (parseInt(new Date().getMonth()) + 1) + "-" + new Date().getDate();
I didn't like adding to the prototype. An alternative would be:
var rightNow = new Date();_x000D_
var res = rightNow.toISOString().slice(0,10).replace(/-/g,"");_x000D_
_x000D_
<!-- Next line is for code snippet output only -->_x000D_
document.body.innerHTML += res;
_x000D_
I hope this function will be useful
function formatDate(dDate,sMode){
var today = dDate;
var dd = today.getDate();
var mm = today.getMonth()+1; //January is 0!
var yyyy = today.getFullYear();
if(dd<10) {
dd = '0'+dd
}
if(mm<10) {
mm = '0'+mm
}
if (sMode+""==""){
sMode = "dd/mm/yyyy";
}
if (sMode == "yyyy-mm-dd"){
return yyyy + "-" + mm + "-" + dd + "";
}
if (sMode == "dd/mm/yyyy"){
return dd + "/" + mm + "/" + yyyy;
}
}
I don't like modifying native objects, and I think multiplication is clearer than the string padding the accepted solution.
function yyyymmdd(dateIn) {_x000D_
var yyyy = dateIn.getFullYear();_x000D_
var mm = dateIn.getMonth() + 1; // getMonth() is zero-based_x000D_
var dd = dateIn.getDate();_x000D_
return String(10000 * yyyy + 100 * mm + dd); // Leading zeros for mm and dd_x000D_
}_x000D_
_x000D_
var today = new Date();_x000D_
console.log(yyyymmdd(today));
_x000D_
You can use the toISOString
function :
var today = new Date();
today.toISOString().substring(0, 10);
It will give you a "yyyy-mm-dd" format.
Here is a more generic approach which allows both date and time components and is identically sortable as either number or string.
Based on the number order of Date ISO format, convert to a local timezone and remove non-digits. i.e.:
// monkey patch version
Date.prototype.IsoNum = function (n) {
var tzoffset = this.getTimezoneOffset() * 60000; //offset in milliseconds
var localISOTime = (new Date(this - tzoffset)).toISOString().slice(0,-1);
return localISOTime.replace(/[-T:\.Z]/g, '').substring(0,n || 20); // YYYYMMDD
}
Usage
var d = new Date();
// Tue Jul 28 2015 15:02:53 GMT+0200 (W. Europe Daylight Time)
console.log(d.IsoNum(8)); // "20150728"
console.log(d.IsoNum(12)); // "201507281502"
console.log(d.IsoNum()); // "20150728150253272"
Another way is to use toLocaleDateString
with a locale that has a big-endian date format standard, such as Sweden, Lithuania, Hungary, South Korea, ...:
date.toLocaleDateString('se')
To remove the delimiters (-
) is just a matter of replacing the non-digits:
console.log( new Date().toLocaleDateString('se').replace(/\D/g, '') );
_x000D_
This does not have the potential error you can get with UTC date formats: the UTC date may be one day off compared to the date in the local time zone.
How about Day.js?
It's only 2KB, and you can also dayjs().format('YYYY-MM-DD')
.
Sure, you can build a specific function for each variation of date string representations. If you consider international date formats you wind up with dozens of specific functions with rediculous names and hard to distinguish.
There is no reasonable function that matches all formats, but there is a reasonable function composition that does:
const pipe2 = f => g => x =>_x000D_
g(f(x));_x000D_
_x000D_
const pipe3 = f => g => h => x =>_x000D_
h(g(f(x)));_x000D_
_x000D_
const invoke = (method, ...args) => o =>_x000D_
o[method] (...args);_x000D_
_x000D_
const padl = (c, n) => s =>_x000D_
c.repeat(n)_x000D_
.concat(s)_x000D_
.slice(-n);_x000D_
_x000D_
const inc = n => n + 1;_x000D_
_x000D_
// generic format date function_x000D_
_x000D_
const formatDate = stor => (...args) => date =>_x000D_
args.map(f => f(date))_x000D_
.join(stor);_x000D_
_x000D_
// MAIN_x000D_
_x000D_
const toYYYYMMDD = formatDate("") (_x000D_
invoke("getFullYear"),_x000D_
pipe3(invoke("getMonth")) (inc) (padl("0", 2)),_x000D_
pipe2(invoke("getDate")) (padl("0", 2)));_x000D_
_x000D_
console.log(toYYYYMMDD(new Date()));
_x000D_
Yes, this is a lot of code. But you can express literally every string date representation by simply changing the function arguments passed to the higher order function formatDate
. Everything is explicit and declarative i.e., you can almost read what's happening.
I usually use the code below when I need to do this.
var date = new Date($.now());
var dateString = (date.getFullYear() + '-'
+ ('0' + (date.getMonth() + 1)).slice(-2)
+ '-' + ('0' + (date.getDate())).slice(-2));
console.log(dateString); //Will print "2015-09-18" when this comment was written
To explain, .slice(-2) gives us the last two characters of the string.
So no matter what, we can add "0" to the day or month, and just ask for the last two since those are always the two we want.
So if the MyDate.getMonth() returns 9, it will be:
("0" + "9") // Giving us "09"
so adding .slice(-2) on that gives us the last two characters which is:
("0" + "9").slice(-2)
"09"
But if date.getMonth() returns 10, it will be:
("0" + "10") // Giving us "010"
so adding .slice(-2) gives us the last two characters, or:
("0" + "10").slice(-2)
"10"
Working from @o-o's answer this will give you back the string of the date according to a format string. You can easily add a 2 digit year regex for the year & milliseconds and the such if you need them.
Date.prototype.getFromFormat = function(format) {
var yyyy = this.getFullYear().toString();
format = format.replace(/yyyy/g, yyyy)
var mm = (this.getMonth()+1).toString();
format = format.replace(/mm/g, (mm[1]?mm:"0"+mm[0]));
var dd = this.getDate().toString();
format = format.replace(/dd/g, (dd[1]?dd:"0"+dd[0]));
var hh = this.getHours().toString();
format = format.replace(/hh/g, (hh[1]?hh:"0"+hh[0]));
var ii = this.getMinutes().toString();
format = format.replace(/ii/g, (ii[1]?ii:"0"+ii[0]));
var ss = this.getSeconds().toString();
format = format.replace(/ss/g, (ss[1]?ss:"0"+ss[0]));
return format;
};
d = new Date();
var date = d.getFromFormat('yyyy-mm-dd hh:ii:ss');
alert(date);
I don't know how efficient that is however, especially perf wise because it uses a lot of regex. It could probably use some work I do not master pure js.
Use padStart:
Date.prototype.yyyymmdd = function() {
return [
this.getFullYear(),
(this.getMonth()+1).toString().padStart(2, '0'), // getMonth() is zero-based
this.getDate().toString().padStart(2, '0')
].join('-');
};
Answering another for Simplicity & readability.
Also, editing existing predefined class members with new methods is not encouraged:
function getDateInYYYYMMDD() {
let currentDate = new Date();
// year
let yyyy = '' + currentDate.getFullYear();
// month
let mm = ('0' + (currentDate.getMonth() + 1)); // prepend 0 // +1 is because Jan is 0
mm = mm.substr(mm.length - 2); // take last 2 chars
// day
let dd = ('0' + currentDate.getDate()); // prepend 0
dd = dd.substr(dd.length - 2); // take last 2 chars
return yyyy + "" + mm + "" + dd;
}
var currentDateYYYYMMDD = getDateInYYYYMMDD();
console.log('currentDateYYYYMMDD: ' + currentDateYYYYMMDD);
var date = new Date();
var formattedDate = moment(date).format('YYYYMMDD');
// UTC/GMT 0_x000D_
document.write('UTC/GMT 0: ' + (new Date()).toISOString().slice(0, 19).replace(/[^0-9]/g, "")); // 20150812013509_x000D_
_x000D_
// Client local time_x000D_
document.write('<br/>Local time: ' + (new Date(Date.now()-(new Date()).getTimezoneOffset() * 60000)).toISOString().slice(0, 19).replace(/[^0-9]/g, "")); // 20150812113509
_x000D_
Plain JS (ES5) solution without any possible date jump issues caused by Date.toISOString() printing in UTC:
var now = new Date();
var todayUTC = new Date(Date.UTC(now.getFullYear(), now.getMonth(), now.getDate()));
return todayUTC.toISOString().slice(0, 10).replace(/-/g, '');
This in response to @weberste's comment on @Pierre Guilbert's answer.
I try to write a simple library for manipulating JavaScript date object. You can try this.
var dateString = timeSolver.getString(date, "YYYYMMDD")
Libarary here: https://github.com/sean1093/timeSolver
It seems that mootools provides Date().format()
: https://mootools.net/more/docs/1.6.0/Types/Date
I'm not sure if it worth including just for this particular task though.
The @o-o solution doesn't work in my case. My solution is the following:
Date.prototype.yyyymmdd = function() {
var mm = this.getMonth() + 1; // getMonth() is zero-based
var dd = this.getDate();
var ret = [this.getFullYear(), (mm<10)?'0':'', mm, (dd<10)?'0':'', dd].join('');
return ret; // padding
};
Source: Stackoverflow.com