Unzipping files in Python

Question

I read through the zipfile documentation  but couldn t understand how to unzip a file  only how to zip a file  How do I unzip all the contents of a zip file into the same directory

User · Answer

You can also import only ZipFile   from zipfile import ZipFile zf   ZipFile  path to file file zip    r   zf extractall  path to extract folder   zf close     Works in Python 2 and Python 3

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If you want to do it in shell  instead of writing code   python3 -m zipfile -e myfiles zip myfiles   myfiles zip is the zip archive and myfiles is the path to extract the files

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If you are using Python 3 2 or later   import zipfile with zipfile ZipFile  file zip   r   as zip ref      zip ref extractall  targetdir     You dont need to use the close or try catch with this as it uses the context manager construction

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Use the extractall method  if you re using Python 2 6   zip   ZipFile  file zip   zip extractall

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zipfile is a somewhat low-level library  Unless you need the specifics that it provides  you can get away with shutil s higher-level functions make archive and unpack archive  make archive is already described in this answer  As for unpack archive  import shutil shutil unpack archive filename  extract dir   unpack archive detects the compression format automatically from the  quot extension quot  of filename   zip   tar gz  etc   and so does make archive  Also  filename and extract dir can be any path-like objects  e g  pathlib Path instances  since Python 3 7

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import zipfile with zipfile ZipFile path to zip file   r   as zip ref      zip ref extractall directory to extract to    That s pretty much it

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try this        import zipfile def un zipFiles path       files os listdir path      for file in files          if file endswith   zip                filePath path     file             zip file   zipfile ZipFile filePath              for names in zip file namelist                    zip file extract names path              zip file close      path   unzip file s path

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from zipfile import ZipFile ZipFile  quot YOURZIP zip quot   extractall  quot YOUR DESTINATION DIRECTORY quot    The directory where you will extract your files doesn t need to exist before  you name it at this moment YOURZIP zip is the name of the zip if your project is in the same directory  If not  use the PATH i e   C         YOURZIP zip Think to escape the   by an other   in the PATH If you have a permission denied try to launch your ide  i e  Anaconda  as administrator YOUR DESTINATION DIRECTORY will be created in the same directory than your project

User · Answer

import os  zip file path    C  AA BB  file list   os listdir path  abs path      for a in file list      x   zip file path      a     print x     abs path append x  for f in abs path      zip zipfile ZipFile f      zip extractall zip file path    This does not contain validation for the file if its not zip  If the folder contains non  zip file it will fail

[python] Unzipping files in Python

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