Okay, so if you don't have LINQ, you could hard-code it:
public int FindMaxAge(List<MyType> list)
{
if (list.Count == 0)
{
throw new InvalidOperationException("Empty list");
}
int maxAge = int.MinValue;
foreach (MyType type in list)
{
if (type.Age > maxAge)
{
maxAge = type.Age;
}
}
return maxAge;
}
Or you could write a more general version, reusable across lots of list types:
public int FindMaxValue<T>(List<T> list, Converter<T, int> projection)
{
if (list.Count == 0)
{
throw new InvalidOperationException("Empty list");
}
int maxValue = int.MinValue;
foreach (T item in list)
{
int value = projection(item);
if (value > maxValue)
{
maxValue = value;
}
}
return maxValue;
}
You can use this with:
// C# 2
int maxAge = FindMaxValue(list, delegate(MyType x) { return x.Age; });
// C# 3
int maxAge = FindMaxValue(list, x => x.Age);
Or you could use LINQBridge :)
In each case, you can return the if block with a simple call to Math.Max if you want. For example:
foreach (T item in list)
{
maxValue = Math.Max(maxValue, projection(item));
}
int max = myList.Max(r => r.Age);
http://msdn.microsoft.com/en-us/library/system.linq.enumerable.max.aspx
Simplest is actually just Age.Max(), you don't need any more code.
thelist.Max(e => e.age);
var maxAge = list.Max(x => x.Age);
How about this way:
List<int> myList = new List<int>(){1, 2, 3, 4}; //or any other type
myList.Sort();
int greatestValue = myList[ myList.Count - 1 ];
You basically let the Sort() method to do the job for you instead of writing your own method. Unless you don't want to sort your collection.
Easiest way is to use System.Linq as previously described
using System.Linq;
public int GetHighestValue(List<MyTypes> list)
{
return list.Count > 0 ? list.Max(t => t.Age) : 0; //could also return -1
}
This is also possible with a Dictionary
using System.Linq;
public int GetHighestValue(Dictionary<MyTypes, OtherType> obj)
{
return obj.Count > 0 ? obj.Max(t => t.Key.Age) : 0; //could also return -1
}
Source: Stackoverflow.com