Floating point exception

Question

I successfully  complied this code    include  lt stdio h gt   include  lt math h gt  int q   int main         srand  time NULL         int n 3      q ceil sqrt n        printf   d n  d n   n q        if n    2          printf   d n is prime   n       else if n   2    0 0    n  lt  2          printf   d n is not prime   n       else               int x          for x   0  x  lt  q  x                 if n   x    0                                printf   d n is not prime   n                   return                            else                 printf   d n is prime   n                       But when I run my code I get the following error      Floating point exception   What does this error mean and how can I fix it

User · Answer

It s caused by n   x where x   0 in the first loop iteration  You can t calculate a modulus with respect to 0

User · Answer

It s caused by n   x  when x is 0   You should have x start at 2 instead  You should not use floating point here at all  since you only need integer operations   General notes    Try to format your code better   Focus on using a consistent style   E g  you have one else that starts immediately after a if brace  not even a space   and another with a newline in between  Don t use globals unless necessary   There is no reason for q to be global  Don t return without a value in a non-void  int  function

User · Answer

http   en wikipedia org wiki Division by zero  http   en wikipedia org wiki Unix signal SIGFPE  This should give you a really good idea  Since a modulus is  in its basic sense  division with a remainder  something   0 IS division by zero and as such  will trigger a SIGFPE being thrown

[c] Floating point exception

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