Bash foreach loop

Question

I have an input  let s say a file   On each line there is a file name  How can I read this file and display the content for each one

User · Answer

foreach  is not the name for bash   It is simply  for    You can do things in one line only like   for fn in  cat filenames txt   do cat   fn   done   Reference  http   www cyberciti biz faq linux-unix-bash-for-loop-one-line-command

User · Answer

Something like this would do   xargs cat  lt filenames txt   The xargs program reads its standard input  and for each line of input runs the cat program with the input lines as argument s    If you really want to do this in a loop  you can   for fn in  cat filenames txt   do     echo  the next file is  fn      cat  fn done

User · Answer

Here is a while loop   while read filename do     echo  Printing   filename      cat   filename  done  lt  filenames txt

User · Answer

xargs --arg-file inputfile cat   This will output the filename followed by the file s contents   xargs --arg-file inputfile -I   sh -c  echo    cat

User · Answer

If they all have the same extension  for example  jpg   you can use this   for picture in    jpg   do     echo  the next file is  picture  done    This solution also works if the filename has spaces

User · Answer

You ll probably want to handle spaces in your file names  abhorrent though they are  -   So I would opt initially for something like   pax gt  cat qq in normalfile txt file with spaces doc  pax gt  sed  s       g  qq in   xargs -n 1 cat  lt  lt contents of  normalfile txt  gt  gt   lt  lt contents of  file with spaces doc  gt  gt   pax gt

User · Answer

cat  cat filenames txt    will do the trick

[bash] Bash foreach loop

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