How to sort a list of lists by a specific index of the inner list

Question

I have a list of lists   For example      0 1  f     4 2  t     9 4  afsd       If I wanted to sort the outer list by the string field of the inner lists  how would you do that in python

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multiple criteria can also be implemented through lambda function  sorted list   sorted list to sort  key lambda x   x 1   x 0

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Make sure that you do not have any null or NaN values in the list you want to sort  If there are NaN values  then your sort will be off  impacting the sorting of the non-null values  Check out Python  sort function breaks in the presence of nan

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I think lambda function can solve your problem   old list     0 1  f     4 2  t    9 4  afsd      let s assume we want to sort lists by last value   old list 2    new list   sorted old list  key lambda x  x 2     Resulst of new list will be     9  4   afsd     0  1   f     4  2   t

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Sorting a Multidimensional Array execute here  arr   2 1   1 2   3 5   4 5   3 1   5 2   3 8   1 9   1 3      arr sort key lambda x x 0   la set  i 0  for i in Points    for i in la      tempres list       for j in arr          if j 0   i              tempres append j 1        for j in sorted tempres reverse True           print i j

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old list     0 1  f     4 2  t    9 4  afsd         let s assume we want to sort lists by last value   old list 2        new list   sorted old list  key lambda x  x 2       correct me if i m wrong but isnt the  x 2   calling the 3rd item in the list  not the 3rd item in the nested list  should it be x 2  2

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Itemgetter lets you to sort by multiple criteria   columns   sorted list   sorted list to sort  key itemgetter 2 0 1

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array sort key   lambda x x 1     You can easily sort using this snippet  where 1 is the index of the element

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This is a job for itemgetter   gt  gt  gt  from operator import itemgetter  gt  gt  gt  L   0  1   f     4  2   t     9  4   afsd     gt  gt  gt  sorted L  key itemgetter 2     9  4   afsd     0  1   f     4  2   t      It is also possible to use a lambda function here  however the lambda function is slower in this simple case

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Like this   import operator l         sorted list   sorted l  key operator itemgetter desired item index

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More easy to understand  What is Lambda actually doing    ls2   0 1  f    4 2  t    9 4  afsd    def thirdItem ls        return the third item of the list     return ls 2   Sort according to what the thirdItem function return  ls2 sort key thirdItem

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in place   gt  gt  gt  l     0  1   f     4  2   t     9  4   afsd     gt  gt  gt  l sort key lambda x  x 2     not in place using sorted    gt  gt  gt  sorted l  key lambda x  x 2

[python] How to sort a list of lists by a specific index of the inner list?

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