Dictionary does not support duplicate keys- So you will get the last key i.e.a=16 but not the first key a=15
>>>qs = [{u'a': 15L, u'b': 9L, u'a': 16L}]
>>>qs
>>>[{u'a': 16L, u'b': 9L}]
>>>result_list = [int(v) for k,v in qs[0].items()]
>>>result_list
>>>[16, 9]