Possible Duplicate:
How to parse a string to an int in C++?
I have done some research and some people say to use atio and others say it's bad, and I can't get it to work anyways.
So I just want to ask flat out, whats the right way to convert a string to a int.
string s = "10";
int i = s....?
Thanks!
You can use istringstream
.
string s = "10";
// create an input stream with your string.
istringstream is(str);
int i;
// use is like an input stream
is >> i;
Some handy quick functions (if you're not using Boost):
template<typename T>
std::string ToString(const T& v)
{
std::ostringstream ss;
ss << v;
return ss.str();
}
template<typename T>
T FromString(const std::string& str)
{
std::istringstream ss(str);
T ret;
ss >> ret;
return ret;
}
Example:
int i = FromString<int>(s);
std::string str = ToString(i);
Works for any streamable types (floats etc). You'll need to #include <sstream>
and possibly also #include <string>
.
You can use boost::lexical_cast:
#include <iostream>
#include <boost/lexical_cast.hpp>
int main( int argc, char* argv[] ){
std::string s1 = "10";
std::string s2 = "abc";
int i;
try {
i = boost::lexical_cast<int>( s1 );
}
catch( boost::bad_lexical_cast & e ){
std::cout << "Exception caught : " << e.what() << std::endl;
}
try {
i = boost::lexical_cast<int>( s2 );
}
catch( boost::bad_lexical_cast & e ){
std::cout << "Exception caught : " << e.what() << std::endl;
}
return 0;
}
There is no "right way". If you want a universal (but suboptimal) solution you can use a boost::lexical cast
.
A common solution for C++ is to use std::ostream
and << operator
. You can use a stringstream
and stringstream::str()
method for conversion to string.
If you really require a fast mechanism (remember the 20/80 rule) you can look for a "dedicated" solution like C++ String Toolkit Library
Best Regards,
Marcin
Source: Stackoverflow.com