[regex] Perl regular expression (using a variable as a search string with Perl operator characters included)

$text_to_search = "example text with [foo] and more";
$search_string = "[foo]";

if ($text_to_search =~ m/$search_string/)
    print "wee";

Please observe the above code. For some reason I would like to find the text "[foo]" in the $text_to_search variable and print "wee" if I find it. To do this I would have to ensure that the [ and ] is substituted with [ and ] to make Perl treat it as characters instead of operators.

How can I do this without having to first replace [ and ] with \[ and \] using a s/// expression?

Use \Q to autoescape any potentially problematic characters in your variable.

if($text_to_search =~ m/\Q$search_string/) print "wee";

You can use quotemeta (\Q \E) if your Perl is version 5.16 or later, but if below you can simply avoid using a regular expression at all.

For example, by using the index command:

if (index($text_to_search, $search_string) > -1) {
    print "wee";
}

Use the quotemeta function:

$text_to_search = "example text with [foo] and more";
$search_string = quotemeta "[foo]";

print "wee" if ($text_to_search =~ /$search_string/);