I have a simple list of ~25 words. I have a varchar field in PostgreSQL, let's say that list is ['foo', 'bar', 'baz']
. I want to find any row in my table that has any of those words. This will work, but I'd like something more elegant.
select *
from table
where (lower(value) like '%foo%' or lower(value) like '%bar%' or lower(value) like '%baz%')
This question is related to
sql
postgresql
One 'elegant' solution would be to use full text search: http://www.postgresql.org/docs/9.0/interactive/textsearch.html. Then you would use full text search queries.
Actually there is an operator for that in PostgreSQL:
SELECT *
FROM table
WHERE lower(value) ~~ ANY('{%foo%,%bar%,%baz%}');
All currently supported versions (9.5 and up) allow pattern matching in addition to LIKE
.
Reference: https://www.postgresql.org/docs/current/functions-matching.html
PostgreSQL also supports full POSIX regular expressions:
select * from table where value ~* 'foo|bar|baz';
The ~*
is for a case insensitive match, ~
is case sensitive.
Another option is to use ANY:
select * from table where value like any (array['%foo%', '%bar%', '%baz%']);
select * from table where value ilike any (array['%foo%', '%bar%', '%baz%']);
You can use ANY with any operator that yields a boolean. I suspect that the regex options would be quicker but ANY is a useful tool to have in your toolbox.
Source: Stackoverflow.com