How do you specify a byte literal in Java

Question

If I have a method   void f byte b     how can I call it with a numeric argument without casting   f 0     gives an error

User · Answer

You have to cast  I m afraid   f  byte 0     I believe that will perform the appropriate conversion at compile-time instead of execution time  so it s not actually going to cause performance penalties  It s just inconvenient

User · Answer

You cannot  A basic numeric constant is considered an integer  or long if followed by a  L    so you must explicitly downcast it to a byte to pass it as a parameter  As far as I know there is no shortcut

User · Answer

You can use a byte literal in Java    sort of       byte f   0      f   0xa    0xa  int literal  gets automatically cast to byte  It s not a real byte literal  see JLS  amp  comments below   but if it quacks like a duck  I call it a duck   What you can t do is this   void foo byte a               foo  0xa       will not compile   You have to cast as follows    foo   byte  0xa       But keep in mind that these will all compile  and they are using  byte literals    void foo byte a                  byte f   0       foo  f   0xa      compiles      foo  f    a       compiles      foo  f   1       compiles   Of course this compiles too      foo   byte  1       compiles

User · Answer

If you re passing literals in code  what s stopping you from simply declaring it ahead of time   byte b   0    Set to desired value  f b

User · Answer

With Java 7 and later version  you can specify a byte literal in this way  byte aByte    byte 0b00100001   Reference  http   docs oracle com javase 8 docs technotes guides language binary-literals html

User · Answer

What about overriding the method with  void f int value      f  byte value       this will allow for f 0

[java] How do you specify a byte literal in Java?

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