Format Float to n decimal places

Question

I need to format a float to  n decimal places   was trying to BigDecimal  but the return value is not correct     public static float Redondear float pNumero  int pCantidadDecimales           the function is call with the values Redondear 625 3f  2      BigDecimal value   new BigDecimal pNumero       value   value setScale pCantidadDecimales  RoundingMode HALF EVEN      here the value is correct  625 30      return value floatValue       but here the values is 625 3     I need to return a float value with the number of decimal places that I specify   I need Float value return not Double

User · Answer

You can use Decimal format if you want to format number into a string, for example:

String a = "123455";
System.out.println(new 
DecimalFormat(".0").format(Float.valueOf(a)));

The output of this code will be:

123455.0

You can add more zeros to the decimal format, depends on the output that you want.

User · Answer

Try this this helped me a lot  BigDecimal roundfinalPrice   new BigDecimal 5652 25622f  setScale 2 BigDecimal ROUND HALF UP     Result will be roundfinalPrice --  5652 26

User · Answer

Take a look at DecimalFormat   You can easily use it to take a number and give it a set number of decimal places   Edit  Example

User · Answer

public static double roundToDouble float d  int decimalPlace            BigDecimal bd   new BigDecimal Float toString d            bd   bd setScale decimalPlace  BigDecimal ROUND HALF UP           return bd doubleValue

User · Answer

I was looking for an answer to this question and later I developed a method     A fair warning  it s rounding up the value   private float limitDigits float number        return Float valueOf String format Locale getDefault       2f   number

User · Answer

This is a much less professional and much more expensive way but it should be easier to understand and more helpful for beginners    public static float roundFloat float F  int roundTo        String num                      for  int count   0  count  lt  roundTo  count             num     0              DecimalFormat df   new DecimalFormat num        df setRoundingMode RoundingMode HALF UP        String S   df format F       F   Float parseFloat S        return F

User · Answer

Kinda surprised nobody s pointed out the direct way to do it  which is easy enough   double roundToDecimalPlaces double value  int decimalPlaces          double shift   Math pow 10 decimalPlaces         return Math round value shift  shift      Pretty sure this does not do half-even rounding though    For what it s worth  half-even rounding is going to be chaotic and unpredictable any time you mix binary-based floating-point values with base-10 arithmetic  I m pretty sure it cannot be done  The basic problem is that a value like 1 105 cannot be represented exactly in floating point  The floating point value is going to be something like 1 105000000000001  or 1 104999999999999  So any attempt to perform half-even rounding is going trip up on representational encoding errors    IEEE floating point implementations will do half-rounding  but they do binary half-rounding  not decimal half-rounding  So you re probably ok

User · Answer

I think what you want ist   return value toString      and use the return value to display   value floatValue      will always return 625 3 because its mainly used to calculate something

User · Answer

Of note  use of DecimalFormat constructor is discouraged  The javadoc for this class states       In general  do not call the DecimalFormat constructors directly  since the NumberFormat factory methods may return subclasses other than DecimalFormat    https   docs oracle com javase 8 docs api java text DecimalFormat html  So what you need to do is  for instance    NumberFormat formatter   NumberFormat getInstance Locale US   formatter setMaximumFractionDigits 2   formatter setMinimumFractionDigits 2   formatter setRoundingMode RoundingMode HALF UP    Float formatedFloat   new Float formatter format floatValue

User · Answer

Here s a quick sample using the DecimalFormat class mentioned by Nick   float f   12 345f  DecimalFormat df   new DecimalFormat    00    System out println df format f      The output of the print statement will be 12 35  Notice that it will round it for you

User · Answer

You may also pass the float value  and use   String format    2f   floatValue    Documentation

[java] Format Float to n decimal places

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