Remove quotes from a character vector in R

Question

Suppose you have a character vector   char  lt - c  one    two    three     When you make reference to an index value  you get the following    gt  char 1   1   one    How can you strip off the quote marks from the return value to get the following    1  one

User · Answer

Try this   even  1  will be removed   gt  cat noquote  quot love quot    love  else just use noquote  gt  noquote  quot love quot    1  love

User · Answer

nump function      gt  nump  lt - function x  print formatC x  format  fg   big mark       quote FALSE    correct answer      x  lt - 1234567890123456    gt  nump x    1  1 234 567 890 123 456

User · Answer

I think I was trying something very similar to the original poster   the get   worked for me   although the name inside the chart was not inherited   Here is the code that worked for me    install it if you dont have it library quantmod     a list of stock tickers myStocks  lt - c  INTC    AAPL    GOOG    LTD      get some stock prices from default service getSymbols myStocks     to pause in between plots par ask TRUE     plot all symbols for  i in 1 length myStocks         chartSeries get myStocks i    subset  last 26 weeks

User · Answer

There are no quotes in the return value  only in the default output from print   when you display the value   Try   gt  print char 1   quote FALSE   1  one   or   gt  cat char 1     n   one   to see the value without quotes

User · Answer

Easiest way is     gt  a    some string   gt  write a  stdout       Can specify stderr   also  some string   Gives you the option to print to stderr if you re doing some error handling printing

User · Answer

as name char 1   will work  although I m not sure why you d ever really want to do this -- the quotes won t get carried over in a paste for example   gt  paste  quot I am counting to quot   char 1   char 2   char 3    1   quot I am counting to one two three quot

User · Answer

Here is one combining noquote and paste   noquote paste  Argument is of length zero  sQuote       and  dQuote  double         1  Argument is of length zero         and    double

User · Answer

If    gt  char lt -c  one    two    three     You can    gt  print char 1  quote   FALSE    Your result should be    1  one

User · Answer

Just try noquote a      noquote  a      1  a

User · Answer

I m just guessing  is this in the ball park of what you re trying to achieve    gt  a  lt -  a   gt  a  1   a    quote yes  gt  as factor a   1  a  quote no

User · Answer

You are confusing quantmod s  symbol   a term relating to a code for some financial thingamuwot  with R s  symbol   which is a  type  in R   You ve said      I have a character vector of stock   symbols that I pass to   quantmod  getSymbols   and the   function returns the symbol to the   environment without the quotes   Well almost  What it does is create objects with those names in the specified environment  What I think you want to do is to get things out of an environment by name  And for that you need  get   Here s how  example code  working in the default environment      getSymbols  F  src  yahoo  return class  ts       1   F    so you have a vector of characters of the things you want    gt  z  F   gt  z  1   F    and then the magic    gt  summary get z        F Open           F High           F Low           F Close        Min      1 310   Min      1 550   Min      1 010   Min      1 260    1st Qu   5 895   1st Qu   6 020   1st Qu   5 705   1st Qu   5 885    Median   7 950   Median   8 030   Median   7 800   Median   7 920    Mean     8 358   Mean     8 495   Mean     8 178   Mean     8 332    3rd Qu  11 210   3rd Qu  11 400   3rd Qu  11 000   3rd Qu  11 180    Max     18 810   Max     18 970   Max     18 610   Max     18 790     and if you don t believe me    gt  identical F get z    1  TRUE

[r] Remove quotes from a character vector in R

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