[c] How do I execute external program within C code in linux with arguments?

The system function invokes a shell to run the command. While this is convenient, it has well known security implications. If you can fully specify the path to the program or script that you want to execute, and you can afford losing the platform independence that system provides, then you can use an execve wrapper as illustrated in the exec_prog function below to more securely execute your program.

Here's how you specify the arguments in the caller:

const char    *my_argv[64] = {"/foo/bar/baz" , "-foo" , "-bar" , NULL};

Then call the exec_prog function like this:

int rc = exec_prog(my_argv);

Here's the exec_prog function:

static int exec_prog(const char **argv)
{
    pid_t   my_pid;
    int     status, timeout /* unused ifdef WAIT_FOR_COMPLETION */;

    if (0 == (my_pid = fork())) {
            if (-1 == execve(argv[0], (char **)argv , NULL)) {
                    perror("child process execve failed [%m]");
                    return -1;
            }
    }

#ifdef WAIT_FOR_COMPLETION
    timeout = 1000;

    while (0 == waitpid(my_pid , &status , WNOHANG)) {
            if ( --timeout < 0 ) {
                    perror("timeout");
                    return -1;
            }
            sleep(1);
    }

    printf("%s WEXITSTATUS %d WIFEXITED %d [status %d]\n",
            argv[0], WEXITSTATUS(status), WIFEXITED(status), status);

    if (1 != WIFEXITED(status) || 0 != WEXITSTATUS(status)) {
            perror("%s failed, halt system");
            return -1;
    }

#endif
    return 0;
}

Remember the includes:

#include <unistd.h>
#include <sys/types.h>
#include <sys/wait.h>
#include <stdio.h>

See related SE post for situations that require communication with the executed program via file descriptors such as stdin and stdout.