I want to run a script, which basically shows an output like this:
Installing XXX... [DONE]
Currently, I print Installing XXX...
first and then I print [DONE]
.
However, I now want to print Installing xxx...
and [DONE]
on the same line.
Any ideas?
This question is related to
python
printing
stdout
line-breaks
I found this solution, and it's working on Python 2.7
# Working on Python 2.7 Linux
import time
import sys
def backspace(n):
print('\r', end='') # use '\r' to go back
for i in range(101): # for 0 to 100
s = str(i) + '%' # string for output
sys.stdout.write(string)
backspace(len(s)) # back for n chars
sys.stdout.flush()
time.sleep(0.2) # sleep for 200ms
If you want to overwrite the previous line (rather than continually adding to it), you can combine \r
with print(),
at the end of the print statement. For example,
from time import sleep
for i in xrange(0, 10):
print("\r{0}".format(i)),
sleep(.5)
print("...DONE!")
will count 0 to 9, replacing the old number in the console. The "...DONE!"
will print on the same line as the last counter, 9.
In your case for the OP, this would allow the console to display percent complete of the install as a "progress bar", where you can define a begin and end character position, and update the markers in between.
print("Installing |XXXXXX | 30%"),
Here a 2.7-compatible version derived from the 3.0 version by @Vadim-Zin4uk:
Python 2
import time
for i in range(101): # for 0 to 100
s = str(i) + '%' # string for output
print '{0}\r'.format(s), # just print and flush
time.sleep(0.2)
For that matter, the 3.0 solution provided looks a little bloated. For example, the backspace method doesn't make use of the integer argument and could probably be done away with altogether.
Python 3
import time
for i in range(101): # for 0 to 100
s = str(i) + '%' # string for output
print('{0}\r'.format(s), end='') # just print and flush
time.sleep(0.2) # sleep for 200ms
Both have been tested and work.
This simple example will print 1-10 on the same line.
for i in range(1,11):
print (i, end=" ")
You should use backspace '\r' or ('\x08') char to go back on previous position in console output
Python 2+:
import time
import sys
def backspace(n):
sys.stdout.write((b'\x08' * n).decode()) # use \x08 char to go back
for i in range(101): # for 0 to 100
s = str(i) + '%' # string for output
sys.stdout.write(s) # just print
sys.stdout.flush() # needed for flush when using \x08
backspace(len(s)) # back n chars
time.sleep(0.2) # sleep for 200ms
Python 3:
import time
def backline():
print('\r', end='') # use '\r' to go back
for i in range(101): # for 0 to 100
s = str(i) + '%' # string for output
print(s, end='') # just print and flush
backline() # back to the beginning of line
time.sleep(0.2) # sleep for 200ms
This code will count from 0% to 100% on one line. Final value will be:
> python test.py
100%
Additional info about flush in this case here: Why do python print statements that contain 'end=' arguments behave differently in while-loops?
Python appends newline as an end to print. Use end=' ' for python3 for print method to append a space instead of a newline. for python2 use comma at end of print statement.
print("Foo",end=' ')
print('Bar')
You can use the print
statement to do this without importing sys
.
def install_xxx():
print "Installing XXX... ",
install_xxx()
print "[DONE]"
The comma on the end of the print
line prevents print
from issuing a new line (you should note that there will be an extra space at the end of the output).
The Python 3 Solution
Since the above does not work in Python 3, you can do this instead (again, without importing sys
):
def install_xxx():
print("Installing XXX... ", end="", flush=True)
install_xxx()
print("[DONE]")
The print function accepts an end
parameter which defaults to "\n"
. Setting it to an empty string prevents it from issuing a new line at the end of the line.
Found this Quora post, with this example which worked for me (python 3), which was closer to what I needed it for (i.e. erasing the whole previous line).
The example they provide:
def clock():
while True:
print(datetime.now().strftime("%H:%M:%S"), end="\r")
For printing the on the same line, as others have suggested, just use end=""
Just in case you have pre-stored the values in an array, you can call them in the following format:
for i in range(0,n):
print arr[i],
print('\r' + 'something to be override', end='')
It means it will back the cursor to beginning, than will print something and will end in the same line. If in a loop it will start printing in the same place it starts.
This is a very old thread, but here's a very thorough answer and sample code.
\r
is the string representation of Carriage Return from the ASCII character set. It's the same as octal 015
[chr(0o15)
] or hexidecimal 0d
[chr(0x0d)
] or decimal 13
[chr(13)
]. See man ascii
for a boring read. It (\r
) is a pretty portable representation and is easy enough for people to read. It very simply means to move the carriage on the typewriter all the way back to the start without advancing the paper. It's the CR
part of CRLF
which means Carriage Return and Line Feed.
print()
is a function in Python 3. In Python 2 (any version that you'd be interested in using), print
can be forced into a function by importing its definition from the __future__
module. The benefit of the print
function is that you can specify what to print at the end, overriding the default behavior of \n
to print a newline at the end of every print()
call.
sys.stdout.flush
tells Python to flush the output of standard output, which is where you send output with print()
unless you specify otherwise. You can also get the same behavior by running with python -u
or setting environment variable PYTHONUNBUFFERED=1
, thereby skipping the import sys
and sys.stdout.flush()
calls. The amount you gain by doing that is almost exactly zero and isn't very easy to debug if you conveniently forget that you have to do that step before your application behaves properly.
And a sample. Note that this runs perfectly in Python 2 or 3.
from __future__ import print_function
import sys
import time
ANS = 42
FACTORS = {n for n in range(1, ANS + 1) if ANS % n == 0}
for i in range(1, ANS + 1):
if i in FACTORS:
print('\r{0:d}'.format(i), end='')
sys.stdout.flush()
time.sleep(ANS / 100.0)
else:
print()
None of the answers worked for me since they all paused until a new line was encountered. I wrote a simple helper:
def print_no_newline(string):
import sys
sys.stdout.write(string)
sys.stdout.flush()
To test it:
import time
print_no_newline('hello ')
# Simulate a long task
time.sleep(2)
print('world')
"hello " will first print out and flush to the screen before the sleep. After that you can use standard print.
sys.stdout.write
will print without return carriage
import sys
sys.stdout.write("installing xxx")
sys.stdout.write(".")
http://en.wikibooks.org/wiki/Python_Programming/Input_and_output#printing_without_commas_or_newlines
Print has an optional end
argument, it is what printed in the end.
The default is a newline, but you can change it to empty string. e.g. print("hello world!", end="")
Use sys.stdout.write('Installing XXX... ')
and sys.stdout.write('Done')
. In this way, you have to add the new line by hand with "\n"
if you want to recreate the print functionality. I think that it might be unnecessary to use curses just for this.
print() has a built in parameter "end" that is by default set to "\n" Calling print("This is America") is actually calling print("This is America", end = "\n"). An easy way to do is to call print("This is America", end ="")
You can simply use this:
print 'something',
...
print ' else',
and the output will be
something else
no need to overkill by import sys
. Pay attention to comma symbol at the end.
Python 3+
print("some string", end="");
to remove the newline insert at the end. Read more by help(print);
Source: Stackoverflow.com