[bash] Bash: Strip trailing linebreak from output

If you want to remove only the last newline, pipe through:

sed -z '$ s/\n$//'

sed won't add a \0 to then end of the stream if the delimiter is set to NUL via -z, whereas to create a POSIX text file (defined to end in a \n), it will always output a final \n without -z.

Eg:

$ { echo foo; echo bar; } | sed -z '$ s/\n$//'; echo tender
foo
bartender

And to prove no NUL added:

$ { echo foo; echo bar; } | sed -z '$ s/\n$//' | xxd
00000000: 666f 6f0a 6261 72                        foo.bar

To remove multiple trailing newlines, pipe through:

sed -Ez '$ s/\n+$//'

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