Format ints into string of hex

Question

I need to create a string of hex digits from a list of random integers  0-255   Each hex digit should be represented by two characters  5 -  05   16 -  10   etc   Example    Input   0 1 2 3 127 200 255    Output  000102037fc8ff    I ve managed to come up with      usr bin env python  def format me nums       result          for i in nums          if i  lt   9              result     0 x    i         else              result      x    i     return result  print format me  0 1 2 3 127 200 255     However  this looks a bit awkward  Is there a simpler way

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From Python documentation  Using the built in format   function you can specify hexadecimal base using an  x  or  X  Example  x  255 print  the number is    x   format x   Output  the number is  ff Here are the base options Type  b  Binary format  Outputs the number in base 2   c  Character  Converts the integer to the corresponding unicode character before printing   d  Decimal Integer  Outputs the number in base 10   o  Octal format  Outputs the number in base 8   x  Hex format  Outputs the number in base 16  using lower- case letters for the digits above 9   X  Hex format  Outputs the number in base 16  using upper- case letters for the digits above 9   n  Number  This is the same as  d   except that it uses the current locale setting to insert the appropriate number separator characters  None    The same as  d

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Similar to my other answer  except repeating the format string    gt  gt  gt  numbers    1  15  255   gt  gt  gt  fmt      02X     len numbers   gt  gt  gt  fmt format  numbers   010FFF

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Example with some beautifying  similar to the sep option available in python 3 8  def prettyhex nums  sep          return sep join f  a 02x   for a in nums   numbers    0  1  2  3  127  200  255  print prettyhex numbers  -      output  00-01-02-03-7f-c8-ff

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The most recent and in my opinion preferred approach is the f-string       join f  i 02x   for i in  1  15  255     Format options  The old format style was the  -syntax      02x  i for i in  1  15  255     The more modern approach is the  format method        02x   format i  for i in  1  15  255     More recently  from python 3 6 upwards we were treated to the f-string syntax     f  i 02x   for i in  1  15  255     Format syntax  Note that the f  i 02x   works as follows     The first part before   is the input or variable to format   The x indicates that the string should be hex  f  100 02x   is  64  and f  100 02d   is  1001   The 02 indicates that the string should be left-filled with 0 s to length 2  f  100 02x   is  64  and f  100 30x   is                              64

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Yet another option is binascii hexlify   a    0 1 2 3 127 200 255  print binascii hexlify bytes bytearray a      prints  000102037fc8ff   This is also the fastest version for large strings on my machine   In Python 2 7 or above  you could improve this even more by using  binascii hexlify memoryview bytearray a      saving the copy created by the bytes call

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Python 2    gt  gt  gt  str bytearray  0 1 2 3 127 200 255    encode  hex    000102037fc8ff    Python 3    gt  gt  gt  bytearray  0 1 2 3 127 200 255   hex    000102037fc8ff

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join   02x  i for i in input

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Just for completeness  using the modern  format   syntax    gt  gt  gt  numbers    1  15  255   gt  gt  gt     join    02X   format a  for a in numbers   010FFF

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With python 2 X  you can do the following   numbers    0  1  2  3  127  200  255  print    join chr i  encode  hex   for i in numbers    print   000102037fc8ff

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a    0 1 2 3 127 200 255  print str join        02x    i for i in a     prints  000102037fc8ff    Also note that your code will fail for integers in the range from 10 to 15

[python] Format ints into string of hex

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