Python reshape list to ndim array

Question

Hi I have a list flat which is length 2800  it contains 100 results for each of 28 variables  Below is an example of 4 results for 2 variables   0   0   1   1   2   2   3   3    I would like to reshape the list to an array  2 4  so that the results for each variable are in a single element      0 1 2 3     0 1 2 3

User · Answer

The answers above are good  Adding a case that I used   Just if you don t want to use numpy and keep it as list without changing the contents      You can run a small loop and change the dimension from 1xN to Nx1        tmp        for b in bus          tmp append  b       bus tmp   It is maybe not efficient while in case of very large numbers  But it works for a small set of numbers  Thanks

User · Answer

You can think of reshaping that the new shape is filled row by row  last dimension varies fastest  from the flattened original list array   An easy solution is to shape the list into a  100  28  array and then transpose it   x   np reshape list data   100  28   T   Update regarding the updated example   np reshape  0  0  1  1  2  2  3  3    4  2   T   array   0  1  2  3             0  1  2  3     np reshape  0  0  1  1  2  2  3  3    2  4     array   0  0  1  1             2  2  3  3

User · Answer

You can specify the interpretation order of the axes using the order parameter  np reshape arr   2  -1   order  F

User · Answer

Step by step         import numpy library import numpy as np   create list my list    0 0 1 1 2 2 3 3    convert list to numpy array np array np asarray my list    reshape array into 4 rows x 2 columns  and transpose the result reshaped array   np array reshape 4  2  T    check the result reshaped array array   0  1  2  3           0  1  2  3

[python] Python reshape list to ndim array

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