[java] What does the following Oracle error mean: invalid column index

I got the following error while testing some code:

SQLException: Invalid column index

What exactly does that mean?

Is there an online document explaining what all the Oracle error codes and statements?

This question is related to java sql oracle

The answer is


I had this problem using a prepared statement. I didn't add enough "?" for the "VALUES" My eclipse had crashed after I did add the proper amount, and lost those changes. But that didn't occur to me to be the error until I started combing through the SQL as p.campbell suggested.


the final sql statement is something like:

select col_1 from table_X where col_2 = 'abcd';

i run this inside my SQL IDE and everything is ok.

Next, i try to build this statement with java:

String queryString= "select col_1 from table_X where col_2 = '?';";
PreparedStatement stmt = con.prepareStatement(queryString);
stmt.setString(1, "abcd"); //raises java.sql.SQLException: Invalid column index

Although the sql statement (the first one, ran against the database) contains quotes around string values, and also finishes with a semicolumn, the string that i pass to the PreparedStatement should not contain quotes around the wildcard character ?, nor should it finish with semicolumn.

i just removed the characters that appear on white background

"select col_1 from table_X where col_2 = ' ? ' ; ";

to obtain

"select col_1 from table_X where col_2 = ?";

(i found the solution here: https://coderanch.com/t/424689/databases/java-sql-SQLException-Invalid-column)


I also got this type error, problem is wrong usage of parameters to statement like, Let's say you have a query like this

SELECT * FROM EMPLOYE E WHERE E.ID = ?

and for the preparedStatement object (JDBC) if you set the parameters like

preparedStatement.setXXX(1,value);
preparedStatement.setXXX(2,value)

then it results in SQLException: Invalid column index

So, I removed that second parameter setting to prepared statement then problem solved


Using Spring's SimpleJdbcTemplate, I got it when I tried to do this:

String sqlString = "select pwy_code from approver where university_id = '123'";
List<Map<String, Object>> rows = getSimpleJdbcTemplate().queryForList(sqlString, uniId);
  • I had an argument to queryForList that didn't correspond to a question mark in the SQL. The first line should have been:

    String sqlString = "select pwy_code from approver where university_id = ?";
    

I had the exact same problem when using Spring Security 3.1.0. and Oracle 11G. I was using the following query and getting the invalid column index error:

<security:jdbc-user-service data-source-ref="dataSource"
                users-by-username-query="SELECT A.user_name AS username, A.password AS password FROM MB_REG_USER A where A.user_name=lower(?)"

It turns out that I needed to add: "1 as enabled" to the query:

<security:jdbc-user-service data-source-ref="dataSource" users-by-username query="SELECT A.user_name AS username, A.password AS password, 1 as enabled FROM MB_REG_USER A where A.user_name=lower(?)"

Everything worked after that. I believe this could be a bug in the Spring JDBC core package...


It sounds like you're trying to SELECT a column that doesn't exist.

Perhaps you're trying to ORDER BY a column that doesn't exist?

Any typos in your SQL statement?


I had this problem in one legacy application that create prepared statement dynamically.

String firstName;
StringBuilder query =new StringBuilder("select id, name from employee where country_Code=1");
query.append("and  name like '");
query.append(firstName + "' ");
query.append("and ssn=?");
PreparedStatement preparedStatement =new prepareStatement(query.toString());

when it try to set value for ssn, it was giving invalid column index error, and finally found out that it is caused by firstName having ' within; that disturb the syntax.


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