[jquery] How to send multiple data fields via Ajax?

I'm stuck: I'm trying to submit a form using AJAX, but I can't find a way to send multiple data fields via my AJAX call.

$(document).ready(function() {
  $("#btnSubmit").click(function()  {
    var status = $("#activitymessage").val();
    var name = "Ronny";
    $.ajax({
      type: "POST",
      url: "ajax/activity_save.php",
      **data: "status="+status+"name="+name"**,
      success: function(msg) {...

I've tried all sorts of stuff:

data: {status: status, name: name},

Or even stuff like this just for testing purposes:

data: "status=testing&name=ronny",

But whatever I try, I get nothing in my activity_save.php thus nothing in my SQL.

So, what's the correct syntax to put more lines of data in my AJAX call?

You can send data through JSON or via normal POST, here is an example for JSON.

 var value1 = 1;
 var value2 = 2;
 var value3 = 3;   
 $.ajax({
      type: "POST",
      contentType: "application/json; charset=utf-8",
      url: "yoururlhere",
      data: { data1: value1, data2: value2, data3: value3 },
      success: function (result) {
           // do something here
      }
 });

If you want to use it via normal post try this

 $.ajax({
      type: "POST",
      url: $('form').attr("action"),   
      data: $('#form0').serialize(),
      success: function (result) {
         // do something here
      }
 });

Here's what works for me after 2 days of head-scratching; why I couldn't get the AJaX 'data' setting to send two key/values (including a variable containing raw image data) was a mystery, but that seems to be what the jQuery.param() function was written for;

create a params array with your variables, without quotes:

var params = { key_name1: var_1, key_name2: var_2  }; // etc.

var ser_data = jQuery.param( params );   // arbitrary variable name

Use variable ser_data as your data value;

      $.ajax({
       type: 'POST',
       url: '../php_handler_url.php',
       data: ser_data,
    }).success(function(response) {
       alert(response);
    });

Documentation is here: https://api.jquery.com/jQuery.param/

Hope that helps!

I am a beginner at ajax but I think to use this "data: {status: status, name: name}" method datatype must be set to JSON i.e

$.ajax({
type: "POST",
dataType: "json",
url: "ajax/activity_save.php",
data: {status: status, name: name},

This one works for me.

Here's my PHP:

<div id="pageContent">
  <?php
    while($row = mysqli_fetch_assoc($stmt)) {
  ?>
  <br/>
  <input id="vendorName_" name="vendorName_<?php echo $row["id"]; ?>" value='<?php echo $row["vendorName"]; ?>'>
  <input id="owner_" name="owner_<?php echo $row["id"]; ?>" value='<?php echo $row["owner"]; ?>'>
  <input id="city_" name="city_<?php echo $row["id"]; ?>" value='<?php echo $row["city"]; ?>'>
  <button id="btn_update_<?php echo $row["id"]; ?>">Update</button>
  <button id="btn_delete_<?php echo $row["id"]; ?>">Delete</button>
  <?php
    }
  ?>
  </br></br>
  <input id = "vendorName_new" value="">
  <input id = "owner_new" value="">
  <input id = "city_new" value="">
  <button id = "addNewVendor" type="submit">+ New Vendor</button>
</div>

Here's my jQuery using AJAX:

$("#addNewVendor").click(function() {
  alert();
  $.ajax({
    type: "POST",
    url: "create.php",
    data: {vendorName: $("#vendorName_new").val(), owner: $("#owner_new").val(), city: $("#city_new").val()},
    success: function(){
      $(this).hide();
      $('div.success').fadeIn();
      showUsers()
    }
  });
});

Try to use :

$.ajax({
    type: "GET",
    url: "something.php",
    data: { "b": data1, "c": data2 },   
    dataType: "html",
    beforeSend: function() {},
    error: function() {
        alert("Error");
    },
    success: function(data) {                                                    
        $("#result").empty();
        $("#result").append(data);
    }
});

var countries = new Array();
countries[0] = 'ga';
countries[1] = 'cd';

after that you can do like:

var new_countries = countries.join(',')

after:

$.ajax({
    type: "POST",
    url: "Concessions.aspx/GetConcessions",
    data: new_countries,
    ...

This thing work as JSON string format.

Use this

data: '{"username":"' + username + '"}',

I try a lot of syntax to work with laravel it work for me for laravel 4.2 + ajax.

Try this:

$(document).ready(function() {
  $("#btnSubmit").click(function() {
    var status = $("#activitymessage").val();
    var name = "Ronny";
    $.ajax({
      type: "POST",
      url: "ajax/activity_save.php",
      data: {'status': status, 'name': name},
        success: function(msg) {...

According to http://api.jquery.com/jquery.ajax/

$.ajax({
  method: "POST",
  url: "some.php",
  data: { name: "John", location: "Boston" }
})
.done(function( msg ) {
  alert( "Data Saved: " + msg );
});

I am new to AJAX and I have tried this and it works well.

function q1mrks(country,m) {
  // alert("hellow");
  if (country.length==0) {
    //alert("hellow");
    document.getElementById("q1mrks").innerHTML="";
    return;
  }
  if (window.XMLHttpRequest) {
    // code for IE7+, Firefox, Chrome, Opera, Safari
    xmlhttp=new XMLHttpRequest();
  } else {
    // code for IE6, IE5
    xmlhttp=new ActiveXObject("Microsoft.XMLHTTP");
  }
  xmlhttp.onreadystatechange=function() {
    if (xmlhttp.readyState==4 && xmlhttp.status==200) {
      document.getElementById("q1mrks").innerHTML=xmlhttp.responseText;
    }
  }
  xmlhttp.open("GET","../location/cal_marks.php?q1mrks="+country+"&marks="+m,true);
  //mygetrequest.open("GET", "basicform.php?name="+namevalue+"&age="+agevalue, true)
  xmlhttp.send();
}

Try with quotes:

data: {"status": status, "name": name}

It must work fine.