Example: "This is just\na simple sentence".
I want to match every character between "This is" and "sentence". Line breaks should be ignored. I can't figure out the correct syntax.
This question is related to
regex
use this: (?<=beginningstringname)(.*\n?)(?=endstringname)
RegEx to match everything between two strings using the Java approach.
List<String> results = new ArrayList<>(); //For storing results
String example = "Code will save the world";
Let's use Pattern and Matcher objects to use RegEx (.?)*.
Pattern p = Pattern.compile("Code "(.*?)" world"); //java.util.regex.Pattern;
Matcher m = p.matcher(example); //java.util.regex.Matcher;
Since Matcher might contain more than one match, we need to loop over the results and store it.
while(m.find()){ //Loop through all matches
results.add(m.group()); //Get value and store in collection.
}
This example will contain only "will save the" word, but in the bigger text it will probably find more matches.
Resurrecting this question because the regex in the accepted answer doesn't seem quite correct to me. Why? Because
(?<=This is)(.*)(?=sentence)
will match my first sentence. This is my second
in This is my first sentence. This is my second sentence.
You need a lazy quantifier between the two lookarounds. Adding a ?
makes the star lazy.
This matches what you want:
(?<=This is).*?(?=sentence)
See demo. I removed the capture group, which was not needed.
DOTALL Mode to Match Across Line Breaks
Note that in the demo the "dot matches line breaks mode" (a.k.a.) dot-all is set (see how to turn on DOTALL in various languages). In many regex flavors, you can set it with the online modifier (?s)
, turning the expression into:
(?s)(?<=This is).*?(?=sentence)
Reference
You can simply use this: \This is .*? \sentence
This worked for me (I'm using VS Code):
for:
This is just\na simple sentence
Use:
This .+ sentence
In sublime text, you simply write the two word you are interested in keeping for example in your case it is
"This is" and "sentence"
and you write .* in between
i.e. This is .* sentence
and this should do you well
This:
This is (.*?) sentence
works in javascript.
I landed here on my search for regex to convert this print syntax between print "string", in Python2 in old scripts with: print("string"), for Python3. Works well, otherwise use 2to3.py for additional conversions. Here is my solution for others:
Try it out on Regexr.com (doesn't work in NP++ for some reason):
find: (?<=print)( ')(.*)(')
replace: ('$2')
for variables:
(?<=print)( )(.*)(\n)
('$2')\n
for label and variable:
(?<=print)( ')(.*)(',)(.*)(\n)
('$2',$4)\n
How to replace all print "string" in Python2 with print("string") for Python3?
Try This is[\s\S]*sentence
, works in javascript
In case anyone is looking for an example of this within a Jenkins context. It parses the build.log and if it finds a match it fails the build with the match.
import java.util.regex.Matcher;
import java.util.regex.Pattern;
node{
stage("parse"){
def file = readFile 'build.log'
def regex = ~"(?s)(firstStringToUse(.*)secondStringToUse)"
Matcher match = regex.matcher(file)
match.find() {
capturedText = match.group(1)
error(capturedText)
}
}
}
There is a way to deal with repeated instances of this split in a block of text? FOr instance: "This is just\na simple sentence. Here is some additional stuff. This is just\na simple sentence. And here is some more stuff. This is just\na simple sentence. ". to matches each instance instead of the entire string, use below code:
data = "This is just\na simple sentence. Here is some additional stuff. This is just\na simple sentence. And here is some more stuff. This is just\na simple sentence."
pattern = re.compile('This is (?s).*? sentence')
for match_instance in re.finditer(pattern, data):
do_something(match_instance.group())
for a quick search in VIM, you could use at Vim Control prompt: /This is.*\_.*sentence
Here is how I did it:
This was easier for me than trying to figure out the specific regex necessary.
int indexPictureData = result.IndexOf("-PictureData:");
int indexIdentity = result.IndexOf("-Identity:");
string returnValue = result.Remove(indexPictureData + 13);
returnValue = returnValue + " [bytecoderemoved] " + result.Remove(0, indexIdentity); `
Source: Stackoverflow.com