CRON job to run on the last day of the month

Question

I need to create a CRON job that will run on the last day of every month  I will create it using cPanel   Any help is appreciated   Thanks

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You could set up a cron job to run on every day of the month  and have it run a shell script like the following   This script works out whether tomorrow s day number is less than today s  i e  if tomorrow is a new month   and then does whatever you want   TODAY  date   d  TOMORROW  date   d -d  1 day      See if tomorrow s day is less than today s if    TOMORROW -lt  TODAY    then echo  This is the last day of the month    Do stuff    fi

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Adapting paxdiablo s solution  I run on the 28th and 29th of February   The data from the 29th overwrites the 28th     min  hr  date     month          dow   55   23  31     1 3 5 7 8 10 12      path monthly copy data sh   55   23  30     4 6 9 11             path monthly copy data sh   55   23  28 29  2                    path monthly copy data sh

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The last day of month can be 28-31 depending on what month it is  Feb  March etc   However in either of these cases  the next day is always 1st of next month  So we can use that to make sure we run some job always on the last day of a month using the code below   0 8 28-31          date   d -d tomorrow      01     amp  amp   your script sh

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For a safer method in a crontab based on  Indie solution  use absolute path to date       does not works on all crontab systems    0 23 28-31         bin date -d  1day    d  -eq 1    amp  amp  myscript sh

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00 23            date    d   -eq   cal   awk         print  NF      tail -1      amp  amp  job   Check out a related question on the unix com forum

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55 23 28-31     echo      date -d  1day   d  -eq 1    amp  amp  my sh     bin bash

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What about this    edit user s  bashprofile adding    export LAST DAY OF MONTH   cal   awk         print  NF      tail -1    Then add this entry to crontab    mm hh     1-7      date    d   -eq  LAST DAY OF MONTH     amp  amp   absolutepath myscript sh

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Set up a cron job to run on the first day of the month  Then change the system s clock to be one day ahead

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Memory Aid    environment    HOME  HOME SHELL  SHELL LOGNAME  LOGNAME PATH  PATH                                                               string         meaning   ------         -------    reboot        Run once  at startup     yearly        Run once a year   0 0 1 1        annually       same as  yearly     monthly       Run once a month   0 0 1          weekly        Run once a week   0 0     0      daily         Run once a day   0 0            midnight       same as  daily     hourly        Run once an hour   0            mm     hh      Mday    Mon     Dow     CMD   minute  hour  month-day month DayofW CMD                                          Minute of the hour                                          Hour in the day  0  23                                           Day of month  1  31  mon tue wed                                           Month  1 12  Jan  Feb   Dec                                          day of the week 0-6  7  0                                          command to be executed  V      V       V       V        V      V                 28-31                      date -d   1 day     d  -eq 1    amp  amp  echo  Tomorrow is the first today now is   date    gt  gt    message 1       0       1                       rm -f   message                 28-31                      date -d   1 day     d  -eq 1    amp  amp  echo  HOME  HOME LOGNAME  LOGNAME SHELL    SHELL PATH  PATH

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You can just connect all answers in one cron line and use only date command   Just check the difference between day of the month which is today and will be tomorrow   0 23       root     expr   date    d -d  1 days   -   date    d     -le 0     amp  amp  echo true   If these difference is below 0 it means that we change the month and there is last day of the month

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What about this one  after Wikipedia   55 23 L      full path to command

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Possibly the easiest way is to simply do three separate jobs   55 23 30 4 6 9 11          myjob sh 55 23 31 1 3 5 7 8 10 12   myjob sh 55 23 28 2                 myjob sh   That will run on the 28th of February though  even on leap years so  if that s a problem  you ll need to find another way     However  it s usually both substantially easier and correct to run the job as soon as possible on the first day of each month  with something like   0 0 1     myjob sh   and modify the script to process the previous month s data   This removes any hassles you may encounter with figuring out which day is the last of the month  and also ensures that all data for that month is available  assuming you re processing data  Running at five minutes to midnight on the last day of the month may see you missing anything that happens between then and midnight   This is the usual way to do it anyway  for most end-of-month jobs     If you still really want to run it on the last day of the month  one option is to simply detect if tomorrow is the first  either as part of your script  or in the crontab itself    So  something like   55 23 28-31           date --date tomorrow    d       01      amp  amp  myjob sh   should be a good start  assuming you have a relatively intelligent date program   If your date program isn t quite advanced enough to give you relative dates  you can just put together a very simple program to give you tomorrow s day of the month  you don t need the full power of date   such as    include  lt stdio h gt   include  lt time h gt   int main  void           Get today  somewhere around midday  no DST issues        time t noonish   time  0       struct tm  localtm   localtime   amp noonish       localtm- gt tm hour   12          Add one day  86 400 seconds        noonish   mktime  localtm    86400      localtm   localtime   amp noonish           Output just day of month       printf    d n   localtm- gt tm mday        return 0      and then use  assuming you ve called it tomdom for  tomorrow s day of month     55 23 28-31           tomdom       1      amp  amp  myjob sh   Though you may want to consider adding error checking since both time   and mktime   can return -1 if something goes wrong  The code above  for reasons of simplicity  does not take that into account

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Some cron implementations support the  L  flag to represent the last day of the month   If you re lucky to be using one of those implementations  it s as simple as   0 55 23 L       That will run at 11 55 pm on the last day of every month   http   www quartz-scheduler org documentation quartz-1 x tutorials crontrigger

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There s a slightly shorter method that can be used similar to one of the ones above  That is       date -d  1day   d  -eq 1    amp  amp  echo  last day of month    Also  the crontab entry could be update to only check on the 28th to 31st as it s pointless running it the other days of the month  Which would give you   0 23 28-31         date -d  1day   d  -eq 1    amp  amp  myscript sh

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For AWS Cloudwatch cron implementation  Scheduling Lambdas  etc    this works   55 23 L         Running at 11 55pm on the last day of each month

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