C trying to swap values in a vector

Question

This is my swap function   template  lt typename t gt  void swap  t amp  x  t amp  y        t temp   x      x   y      y   temp      return      And this is my function  on a side note v stores strings  call to swap values but whenever I try to call using values in a vector I get an error  I m not sure what I m doing wrong   swap v position   v nextposition      creates errors

User · Answer

I think what you are looking for is iter swap which you can find also in   lt algorithm gt   all you need to do is just pass two iterators each pointing at one of the elements you want to exchange  since you have the position of the two elements  you can do something like this        assuming your vector is called v iter swap v begin     position  v begin     next position      position  next position are the indices of the elements you want to swap

User · Answer

There is a std  swap in  lt algorithm gt

User · Answer

after passing the vector by reference   swap vector position  vector otherPosition      will produce the expected result

User · Answer

Both proposed possibilities  std  swap and std  iter swap  work  they just have a slightly different syntax   Let s swap a vector s first and second element  v 0  and v 1    We can swap based on the objects contents   std  swap v 0  v 1      Or swap based on the underlying iterator   std  iter swap v begin   v begin   1     Try it   int main       int arr      1 2 3 4 5 6 7 8 9     std  vector lt int gt    v   new std  vector lt int gt  arr  arr   sizeof arr    sizeof arr 0          put one of the above swap lines here           for  std  vector lt int gt   iterator i v- gt begin    i  v- gt end    i        std  cout  lt  lt   i  lt  lt         std  cout  lt  lt  std  endl      Both times you get the first two elements swapped   2 1 3 4 5 6 7 8 9

[c++] C++ trying to swap values in a vector

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