Why I cannot cout a string

Question

Why I cannot cout string like this   string text   text   WordList i  substr 0 20    cout  lt  lt   String is       lt  lt  text  lt  lt  endl     When I do this  I get the following error      Error 2   error C2679  binary   lt  lt     no operator found which takes a right-hand operand of type  std  string   or there is no acceptable conversion   c  users mollasadra documents visual studio 2008 projects barnamec barnamec barnamec cpp    67  barnamec     It is amazing  that even this is not working   string text   text    hello     cout  lt  lt   String is       lt  lt  text  lt  lt  endl

User · Answer

There are several problems with your code    WordList is not defined anywhere  You should define it before you use it  You can t just write code outside a function like this  You need to put it in a function  You need to  include  lt string gt  before you can use the string class and iostream before you use cout or endl  string  cout and endl live in the std namespace  so you can not access them without prefixing them with std   unless you use the using directive to bring them into scope first

User · Answer

You do not have to reference std  cout or std  endl explicitly  They are both included in the namespace std  using namespace std instead of using scope resolution operator    every time makes is easier and cleaner     include lt iostream gt   include lt string gt  using namespace std

User · Answer

You need to include    include  lt string gt   include  lt iostream gt

User · Answer

You need to reference the cout s namespace std somehow  For instance  insert   using std  cout  using std  endl    on top of your function definition  or the file

User · Answer

Use c str   to convert the std  string to const char     cout  lt  lt   String is       lt  lt  text c str    lt  lt  endl

User · Answer

If you are using linux system then you need to add  using namespace std   Below headers  If windows then make sure you put headers correctly   include lt iostream h gt    include lt string h gt   Refer this it work perfectly    include  lt iostream gt   include  lt string gt   int main      std  string str  We think in generalities  but we live in details                                               quoting Alfred N  Whitehead     std  string str2   str substr  3 5           think      std  size t pos   str find  live            position of  live  in str    std  string str3   str substr  pos           get from  live  to the end    std  cout  lt  lt  str2  lt  lt       lt  lt  str3  lt  lt    n      return 0

User · Answer

Above answers are good but If you do not want to add string include  you can use the following   ostream amp  operator lt  lt  ostream amp  os  string amp  msg    os lt  lt msg c str     return os

[c++] Why I cannot cout a string?

Examples related to c++

Examples related to string

Examples related to cout