Recursively find all files newer than a given time

Question

Given a time t     date -ur 1312603983 Sat  6 Aug 2011 04 13 03 UTC   I m looking for a bash one-liner that lists all files newer  The comparison should take the timezone into account   Something like  find   --newer 1312603983   But with a time t instead of a file

User · Answer

So there s another way  and it is portable to some extent    python  lt  lt EOF import fnmatch import os import os path as path import time  matches      def find dirname None  newerThan 3 24 3600  olderThan None       for root  dirnames  filenames in os walk dirname or               for filename in fnmatch filter filenames                    filepath   os path join root  filename              matches append path              ts now   time time               newer   ts now - path getmtime filepath   lt  newerThan             older   ts now - path getmtime filepath   gt  newerThan             if newerThan and newer or olderThan and older  print filepath     for dirname in dirnames          if dirname not in                          print  dir    dirname             find dirname  find      EOF     xargs -I      echo found file modified within 3 days

User · Answer

Maybe someone can use it  Find all files which were modified within a certain time frame recursively  just run   find   -type f -newermt  2013-06-01     -newermt  2013-06-20

User · Answer

This is a bit circuitous because touch doesn t take a raw time t value  but it should do the job pretty safely in a script    The -r option to date is present in MacOS X  I ve not double-checked GNU    The  time  variable could be avoided by writing the command substitution directly in the touch command line   time   date -r 1312603983    Y m d H M  S   marker  tmp marker    trap  rm -f  marker  exit 1  0 1 2 3 13 15 touch -t  time  marker find   -type f -newer  marker rm -f  marker trap 0

User · Answer

You can find every file what is created modified in the last day  use this example   find  directory -newermt   date   Y- m- d -d  1 day ago   -type f -print   for finding everything in the last week  use  1 week ago  or  7 day ago  anything you want

User · Answer

Given a unix timestamp  seconds since epoch  of 1494500000  do   find   -type f -newermt    date    Y- m- d  H  M  S  -d  1494500000     To grep those files for  foo    find   -type f -newermt    date    Y- m- d  H  M  S  -d  1494500000   -exec grep -H  foo

User · Answer

You can also do this without a marker file   The  s format to date is seconds since the epoch   find s -mmin flag takes an argument in minutes  so divide the difference in seconds by 60   And the  -  in front of age means find files whose last modification is less than age   time 1312603983 now   date    s     age    now - time    60   find   -type f -mmin - age   With newer versions of gnu find you can use -newermt  which makes it trivial

User · Answer

Assuming a modern release  find -newermt is powerful   find -newermt  10 minutes ago     other units work too  see  Date input formats    or  if you want to specify a time t  seconds since epoch    find -newermt  1568670245     For reference  -newermt is not directly listed in the man page for find   Instead  it is shown as -newerXY  where XY are placeholders for mt   Other replacements are legal  but not applicable for this solution   From man find -newerXY      Time specifications are interpreted as for the argument to the -d option of GNU date    So the following are equivalent to the initial example   find -newermt    date    Y- m- d  H  M  S  -d  10 minutes ago       long form using  date  find -newermt     date   s -d  10 minutes ago       short form using  date  -- notice       The date -d  and find -newermt  arguments are quite flexible  but the documentation is obscure   Here s one source that seems to be on point  Date input formats

[linux] Recursively find all files newer than a given time

Examples related to linux

Examples related to bash