[java] How can I count the number of matches for a regex?

If you want to use Java 8 streams and are allergic to while loops, you could try this:

public static int countPattern(String references, Pattern referencePattern) {
    Matcher matcher = referencePattern.matcher(references);
    return Stream.iterate(0, i -> i + 1)
            .filter(i -> !matcher.find())
            .findFirst()
            .get();
}

Disclaimer: this only works for disjoint matches.

Example:

public static void main(String[] args) throws ParseException {
    Pattern referencePattern = Pattern.compile("PASSENGER:\\d+");
    System.out.println(countPattern("[ \"PASSENGER:1\", \"PASSENGER:2\", \"AIR:1\", \"AIR:2\", \"FOP:2\" ]", referencePattern));
    System.out.println(countPattern("[ \"AIR:1\", \"AIR:2\", \"FOP:2\" ]", referencePattern));
    System.out.println(countPattern("[ \"AIR:1\", \"AIR:2\", \"FOP:2\", \"PASSENGER:1\" ]", referencePattern));
    System.out.println(countPattern("[  ]", referencePattern));
}

This prints out:

2
0
1
0

This is a solution for disjoint matches with streams:

public static int countPattern(String references, Pattern referencePattern) {
    return StreamSupport.stream(Spliterators.spliteratorUnknownSize(
            new Iterator<Integer>() {
                Matcher matcher = referencePattern.matcher(references);
                int from = 0;

                @Override
                public boolean hasNext() {
                    return matcher.find(from);
                }

                @Override
                public Integer next() {
                    from = matcher.start() + 1;
                    return 1;
                }
            },
            Spliterator.IMMUTABLE), false).reduce(0, (a, c) -> a + c);
}