Consider these tables (Standard SQL code, runs on SQL Server 2008):
WITH A
AS
(
SELECT *
FROM (
VALUES (1),
(2),
(3),
(4),
(5),
(6)
) AS T (col)
),
B
AS
(
SELECT *
FROM (
VALUES (9),
(8),
(7),
(6),
(5),
(4)
) AS T (col)
), ...
The desired effect is this to sort table A by col ascending, sort table B by col descending then unioning the two, removing duplicates, retaining order before the union and leaving table A results on the "top" with table B on the "bottom" e.g. (pesudo code)
(
SELECT *
FROM A
ORDER
BY col
)
UNION
(
SELECT *
FROM B
ORDER
BY col DESC
);
Of course, this won't work in SQL because there can only be one ORDER BY clause and it can only be applied to the top level table expression (or whatever the output of a SELECT query is known as; I call it the "resultset").
The first thing to address is the intersection between the two tables, in this case the values 4, 5 and 6. How the intersection should be sorted needs to be specified in SQL code, therefore it is desirable that the designer specifies this too! (i.e. the person asking the question, in this case).
The implication in this case would seem to be that the intersection ("duplicates") should be sorted within the results for table A. Therefore, the sorted resultset should look like this:
VALUES (1), -- A including intersection, ascending
(2), -- A including intersection, ascending
(3), -- A including intersection, ascending
(4), -- A including intersection, ascending
(5), -- A including intersection, ascending
(6), -- A including intersection, ascending
(9), -- B only, descending
(8), -- B only, descending
(7), -- B only, descending
Note in SQL "top" and "bottom" has no inferent meaning and a table (other than a resultset) has no inherent ordering. Also (to cut a long story short) consider that UNION removes duplicate rows by implication and must be applied before ORDER BY. The conclusion has to be that each table's sort order must be explicitly defined by exposing a sort order column(s) before being unioned. For this we can use the ROW_NUMBER() windowed function e.g.
...
A_ranked
AS
(
SELECT col,
ROW_NUMBER() OVER (ORDER BY col) AS sort_order_1
FROM A -- include the intersection
),
B_ranked
AS
(
SELECT *,
ROW_NUMBER() OVER (ORDER BY col DESC) AS sort_order_1
FROM B
WHERE NOT EXISTS ( -- exclude the intersection
SELECT *
FROM A
WHERE A.col = B.col
)
)
SELECT *, 1 AS sort_order_0
FROM A_ranked
UNION
SELECT *, 2 AS sort_order_0
FROM B_ranked
ORDER BY sort_order_0, sort_order_1;