[c++] How can I convert a std::string to int?

Just have a quick question. I've looked around the internet quite a bit and I've found a few solutions but none of them have worked yet. Looking at converting a string to an int and I don't mean ASCII codes.

For a quick run-down, we are passed in an equation as a string. We are to break it down, format it correctly and solve the linear equations. Now, in saying that, I'm not able to convert a string to an int.

I know that the string will be in either the format (-5) or (25) etc. so it's definitely an int. But how do we extract that from a string?

One way I was thinking is running a for/while loop through the string, check for a digit, extract all the digits after that and then look to see if there was a leading '-', if there is, multiply the int by -1.

It seems a bit over complicated for such a small problem though. Any ideas?

This question is related to c++ string int

The answer is


The possible options are described below:

1. First option: sscanf()

    #include <cstdio>
    #include <string>

        int i;
        float f;
        double d;
        std::string str;

        // string -> integer
        if(sscanf(str.c_str(), "%d", &i) != 1)
            // error management

        // string -> float
        if(sscanf(str.c_str(), "%f", &f) != 1)
            // error management

        // string -> double 
        if(sscanf(str.c_str(), "%lf", &d) != 1)
            // error management

This is an error (also shown by cppcheck) because "scanf without field width limits can crash with huge input data on some versions of libc" (see here, and here).

2. Second option: std::sto*()

    #include <iostream>
    #include <string>

        int i;
        float f;
        double d;
        std::string str;

        try {
            // string -> integer
            int i = std::stoi(str);

            // string -> float
            float f = std::stof(str);

            // string -> double 
            double d = std::stod(str);
        } catch (...) {
            // error management
        }   

This solution is short and elegant, but it is available only on on C++11 compliant compilers.

3. Third option: sstreams

    #include <string>
    #include <sstream>

        int i;
        float f;
        double d;
        std::string str;

        // string -> integer
        std::istringstream ( str ) >> i;

        // string -> float
        std::istringstream ( str ) >> f;

        // string -> double 
        std::istringstream ( str ) >> d;

        // error management ??

However, with this solution is hard to distinguish between bad input (see here).

4. Fourth option: Boost's lexical_cast

    #include <boost/lexical_cast.hpp>
    #include <string>

        std::string str;

        try {
            int i = boost::lexical_cast<int>( str.c_str());
            float f = boost::lexical_cast<int>( str.c_str());
            double d = boost::lexical_cast<int>( str.c_str());
            } catch( boost::bad_lexical_cast const& ) {
                // Error management
        }

However, this is just a wrapper of sstream, and the documentation suggests to use sstream for better error management (see here).

5. Fifth option: strto*()

This solution is very long, due to error management, and it is described here. Since no function returns a plain int, a conversion is needed in case of integer (see here for how this conversion can be achieved).

6. Sixth option: Qt

    #include <QString>
    #include <string>

        bool ok;
        std::string;

        int i = QString::fromStdString(str).toInt(&ok);
        if (!ok)
            // Error management

        float f = QString::fromStdString(str).toFloat(&ok);
        if (!ok)
            // Error management 

        double d = QString::fromStdString(str).toDouble(&ok);
        if (!ok)
    // Error management     

Conclusions

Summing up, the best solution is C++11 std::stoi() or, as a second option, the use of Qt libraries. All other solutions are discouraged or buggy.


What about Boost.Lexical_cast?

Here is their example:

The following example treats command line arguments as a sequence of numeric data:

int main(int argc, char * argv[])
{
    using boost::lexical_cast;
    using boost::bad_lexical_cast;

    std::vector<short> args;

    while(*++argv)
    {
        try
        {
            args.push_back(lexical_cast<short>(*argv));
        }
        catch(bad_lexical_cast &)
        {
            args.push_back(0);
        }
    }
    ...
}

I know this question is really old but I think there's a better way of doing this

#include <string>
#include <sstream>

bool string_to_int(std::string value, int * result) {
  std::stringstream stream1, stream2;
  std::string stringednumber;
  int tempnumber;
  stream1 << value;
  stream1 >> tempnumber;
  stream2 << tempnumber;
  stream2 >> stringednumber;
  if (!value.compare(stringednumber)) {
    *result = tempnumber;
    return true;
  }
  else return false;
}

If I wrote the code right, this will return a boolean value that tells you if the string was a valid number, if false, it wasn't a number, if true it was a number and that number is now result, you would call this this way:

std::string input;
std::cin >> input;
bool worked = string_to_int(input, &result);

It's probably a bit of overkill, but boost::lexical_cast<int>( theString ) should to the job quite well.


std::istringstream ss(thestring);
ss >> thevalue;

To be fully correct you'll want to check the error flags.


use the atoi function to convert the string to an integer:

string a = "25";

int b = atoi(a.c_str());

http://www.cplusplus.com/reference/clibrary/cstdlib/atoi/


To convert from string representation to integer value, we can use std::stringstream.

if the value converted is out of range for integer data type, it returns INT_MIN or INT_MAX.

Also if the string value can’t be represented as an valid int data type, then 0 is returned.

#include 
#include 
#include 

int main() {

    std::string x = "50";
    int y;
    std::istringstream(x) >> y;
    std::cout << y << '\n';
    return 0;
}

Output: 50

As per the above output, we can see it converted from string numbers to integer number.

Source and more at string to int c++


My Code:

#include <iostream>
using namespace std;

int main()
{
    string s="32";  //String
    int n=stoi(s);  //Convert to int
    cout << n + 1 << endl;

    return 0;
}

If you wot hard code :)

bool strCanBeInt(std::string string){
    for (char n : string) {
        if (n != '0' && n != '1' && n != '2' && n != '3' && n != '4' && n != '5'
            && n != '6' && n != '7' && n != '8' && n != '9') {
            return false;
        }
    }
    return true;
}

int strToInt(std::string string) {
    int integer = 0;
    int numInt;
    for (char n : string) {
        if(n == '0') numInt = 0;
        if(n == '1') numInt = 1;
        if(n == '2') numInt = 2;
        if(n == '3') numInt = 3;
        if(n == '4') numInt = 4;
        if(n == '5') numInt = 5;
        if(n == '6') numInt = 6;
        if(n == '7') numInt = 7;
        if(n == '8') numInt = 8;
        if(n == '9') numInt = 9;
        if (integer){
            integer *= 10;
        }
        integer += numInt;
    }
    return integer;
}

To be more exhaustive (and as it has been requested in comments), I add the solution given by C++17 using std::from_chars.

std::string str = "10";
int number;
std::from_chars(str.data(), str.data()+str.size(), number);

If you want to check whether the conversion was successful:

std::string str = "10";
int number;
auto [ptr, ec] = std::from_chars(str.data(), str.data()+str.size(), number);
assert(ec == std::errc{});
// ptr points to chars after read number

Moreover, to compare the performance of all these solutions, see the following quick-bench link: https://quick-bench.com/q/GBzK53Gc-YSWpEA9XskSZLU963Y

(std::from_chars is the fastest and std::istringstream is the slowest)


One line version: long n = strtol(s.c_str(), NULL, base); .

(s is the string, and base is an int such as 2, 8, 10, 16.)

You can refer to this link for more details of strtol.


The core idea is to use strtol function, which is included in cstdlib.

Since strtol only handles with char array, we need to convert string to char array. You can refer to this link.

An example:

#include <iostream>
#include <string>   // string type
#include <bitset>   // bitset type used in the output

int main(){
    s = "1111000001011010";
    long t = strtol(s.c_str(), NULL, 2); // 2 is the base which parse the string

    cout << s << endl;
    cout << t << endl;
    cout << hex << t << endl;
    cout << bitset<16> (t) << endl;

    return 0;
}

which will output:

1111000001011010
61530
f05a
1111000001011010

In Windows, you could use:

const std::wstring hex = L"0x13";
const std::wstring dec = L"19";

int ret;
if (StrToIntEx(hex.c_str(), STIF_SUPPORT_HEX, &ret)) {
    std::cout << ret << "\n";
}
if (StrToIntEx(dec.c_str(), STIF_SUPPORT_HEX, &ret)) {
    std::cout << ret << "\n";
}

strtol,stringstream need to specify the base if you need to interpret hexdecimal.


Admittedly, my solution wouldn't work for negative integers, but it will extract all positive integers from input text containing integers. It makes use of numeric_only locale:

int main() {
        int num;
        std::cin.imbue(std::locale(std::locale(), new numeric_only()));
        while ( std::cin >> num)
             std::cout << num << std::endl;
        return 0;
}

Input text:

 the format (-5) or (25) etc... some text.. and then.. 7987...78hjh.hhjg9878

Output integers:

 5
25
7987
78
9878

The class numeric_only is defined as:

struct numeric_only: std::ctype<char> 
{
    numeric_only(): std::ctype<char>(get_table()) {}

    static std::ctype_base::mask const* get_table()
    {
        static std::vector<std::ctype_base::mask> 
            rc(std::ctype<char>::table_size,std::ctype_base::space);

        std::fill(&rc['0'], &rc[':'], std::ctype_base::digit);
        return &rc[0];
    }
};

Complete online demo : http://ideone.com/dRWSj


1. std::stoi

std::string str = "10";  
int number = std::stoi(str); 

2. string streams

std::string str = "10";  
int number;  
std::istringstream(str) >> number

3. boost::lexical_cast

#include <boost/lexical_cast.hpp>
std::string str = "10";  
int number;
    
try 
{
    number = boost::lexical_cast<int>(str);
    std::cout << number << std::endl;
}
catch (boost::bad_lexical_cast const &e) // bad input
{
    std::cout << "error" << std::endl;
}

4. std::atoi

std::string str = "10";
int number = std::atoi(str.c_str()); 

5. sscanf()

 std::string str = "10";
 int number;
 if (sscanf(str .c_str(), "%d", &number) == 1) 
 {
     std::cout << number << '\n';
 } 
 else 
 {
     std::cout << "Bad Input";
 }

Well, lot of answers, lot of possibilities. What I am missing here is some universal method that converts a string to different C++ integral types (short, int, long, bool, ...). I came up with following solution:

#include<sstream>
#include<exception>
#include<string>
#include<type_traits>

using namespace std;

template<typename T>
T toIntegralType(const string &str) {
    static_assert(is_integral<T>::value, "Integral type required.");
    T ret;
    stringstream ss(str);
    ss >> ret;
    if ( to_string(ret) != str)
        throw invalid_argument("Can't convert " + str);
    return ret;
}

Here are examples of usage:

string str = "123";
int x = toIntegralType<int>(str); // x = 123

str = "123a";
x = toIntegralType<int>(str); // throws exception, because "123a" is not int

str = "1";
bool y = toIntegralType<bool>(str); // y is true
str = "0";
y = toIntegralType<bool>(str); // y is false
str = "00";
y = toIntegralType<bool>(str); // throws exception

Why not just use stringstream output operator to convert a string into an integral type? Here is the answer: Let's say a string contains a value that exceeds the limit for intended integral type. For examle, on Wndows 64 max int is 2147483647. Let's assign to a string a value max int + 1: string str = "2147483648". Now, when converting the string to an int:

stringstream ss(str);
int x;
ss >> x;

x becomes 2147483647, what is definitely an error: string "2147483648" was not supposed to be converted to the int 2147483647. The provided function toIntegralType spots such errors and throws exception.


 int stringToInt(std::string value) {    
 if(value.length() == 0 ) return 0; //tu zmiana..

 if (value.find(  std::string("NULL") ) != std::string::npos) {
     return 0;
  }
 
  if (value.find(  std::string("null") ) != std::string::npos) {
     return 0;
  }
 
 
int i;
std::stringstream stream1;
stream1.clear();
stream1.str(value);
stream1 >> i;
return i;

};


ll toll(string a){
    ll ret=0;
    bool minus=false;
    for(auto i:a){
        if(i=='-'){ minus=true; continue; }
        ret*=10;
        ret+=(i-'0');
    } if(minus) ret*=-1;
    return ret;
    # ll is defined as, #define ll long long int
    # usage: ll a = toll(string("-1234"));
}

there is another easy way : suppose you have a character like c='4' therefore you can do one of these steps :

1st : int q

q=(int) c ; (q is now 52 in ascii table ) . q=q-48; remember that adding 48 to digits is their ascii code .

the second way :

q=c-'0'; the same , character '0' means 48


atoi is a built-in function that converts a string to an integer, assuming that the string begins with an integer representation.

http://www.cplusplus.com/reference/clibrary/cstdlib/atoi/


From http://www.cplusplus.com/reference/string/stoi/

// stoi example
#include <iostream>   // std::cout
#include <string>     // std::string, std::stoi

int main ()
{
  std::string str_dec = "2001, A Space Odyssey";
  std::string str_hex = "40c3";
  std::string str_bin = "-10010110001";
  std::string str_auto = "0x7f";

  std::string::size_type sz;   // alias of size_t

  int i_dec = std::stoi (str_dec,&sz);
  int i_hex = std::stoi (str_hex,nullptr,16);
  int i_bin = std::stoi (str_bin,nullptr,2);
  int i_auto = std::stoi (str_auto,nullptr,0);

  std::cout << str_dec << ": " << i_dec << " and [" << str_dec.substr(sz) << "]\n";
  std::cout << str_hex << ": " << i_hex << '\n';
  std::cout << str_bin << ": " << i_bin << '\n';
  std::cout << str_auto << ": " << i_auto << '\n';

  return 0;
}

Output:

2001, A Space Odyssey: 2001 and [, A Space Odyssey]

40c3: 16579

-10010110001: -1201

0x7f: 127


Examples related to c++

Method Call Chaining; returning a pointer vs a reference? How can I tell if an algorithm is efficient? Difference between opening a file in binary vs text How can compare-and-swap be used for a wait-free mutual exclusion for any shared data structure? Install Qt on Ubuntu #include errors detected in vscode Cannot open include file: 'stdio.h' - Visual Studio Community 2017 - C++ Error How to fix the error "Windows SDK version 8.1" was not found? Visual Studio 2017 errors on standard headers How do I check if a Key is pressed on C++

Examples related to string

How to split a string in two and store it in a field String method cannot be found in a main class method Kotlin - How to correctly concatenate a String Replacing a character from a certain index Remove quotes from String in Python Detect whether a Python string is a number or a letter How does String substring work in Swift How does String.Index work in Swift swift 3.0 Data to String? How to parse JSON string in Typescript

Examples related to int

How can I convert a char to int in Java? How to take the nth digit of a number in python "OverflowError: Python int too large to convert to C long" on windows but not mac Pandas: Subtracting two date columns and the result being an integer Convert bytes to int? How to round a Double to the nearest Int in swift? Leading zeros for Int in Swift C convert floating point to int Convert Int to String in Swift Converting String to Int with Swift